Please read the attached file
You will use a2+b2=c2 (squared).The leg will represent the a2 or either b2 and the hypotenuse will be the c2.After filling in the variables you will then subtract the a2 which is the leg from the c2 which is the hypotenuse.And then you will factor it or square root it.If you square root it and it’s not a feasible answer then use the Christmas tree or birthday cake method to factor the answer and then you’ll have the value of b2 which is the unknown leg.
1. The remaing area of the yard will be found as follows:
Area of the yard
A1=length*width=10x*15x=150x^2 yd^2
area of the fountain
A2=πr²
A2=π(4x)²
=50.266x^2
The remaining area will be:
A=150x^2-50.266x^2
A=99.735x^2 yd^2
2] Area left for bleachers, restrooms and other parts of the stadium will be as follows:
Area of the lot is:
A1=length*width
A1=8x×12x= 96x^2
Area of the field
A2=length×width
A2=3x×6x=18x^2
Hence the remaining area will be:
A1-A2
=96x^2-18x^2
=78x^2 sq. units
You can’t see it the picture isnt clear
D and I goes to the red house
