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Svetlanka [38]
3 years ago
10

Multiply 3x^2-2x and 2x^2+3x-1

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

6x^{4} + 5x³ - 9x² + 2x

Step-by-step explanation:

Given

(3x² - 2x)(2x² + 3x - 1)

Each term in the second factor is multiplied by each term in the first factor, that is

= 3x²(2x² + 3x - 1) - 2x(2x² + 3x - 1) ← distribute both parenthesis

= 6x^{4} + 9x³ - 3x² - 4x³ - 6x² + 2x ← collect like terms

= 6x^{4} + 5x³ - 9x² + 2x

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A national interest rate on houses for 25 years is 4.3%. A banker in a large northwestern city believes that the local interest
stepladder [879]
The national interest rate on houses for 25 years is 4.3%. The banker wishes to test that the local interest rates are lower than the national rate. So he should use the initial data of 4.3% interest as his base data. Then he should investigate the rates of houses in the local vicinities and compare it to his base data. 
7 0
3 years ago
Simplify the expression.<br> -5+i /2i
Andrei [34K]

Answer:

\frac{1+5i}{2}

Step-by-step explanation:

We know i×i=i^2 which has value of -1.

We will multiply numerator and denominator by i so the denominator will no longer contain imaginary part(s).

Also multiplying by i/i does not change the value of the fraction because i/i=1.

Numerator × i gives (-5+i)i=-5i+i^2=-5i-1

=-1-5i.

Denominator × i gives (2i)i=2i^2=-2.

So the simplified version of this fraction given is:

\frac{-1-5i}{-2}=\frac{1+5i}{2}

The last simplification come from me multiplying fraction by -1/-1.

6 0
3 years ago
The ages of the members of a legislature from a particular state are listed below. Find the​ mean, median, and mode of the data​
Ad libitum [116K]

Answer:

Mean: 46

Median: 43

Mode: 43

Step-by-step explanation:

I hope this helped. I am sorry if you get this wrong.

7 0
3 years ago
PLS HELP THIS ONE!!! IF YOU GOT RIGHT YOU WILL GET BRAINLIEST!!(pls don't miss around else report)
8_murik_8 [283]

Answer:

E. is the correct answer

Step-by-step explanation:

8 0
3 years ago
The equation 2x^2 + x - 1 = 0 has two solutions. Find an equation of the form ax^2 + bx + c = 0, which solutions....
leonid [27]

Answer:

Step-by-step explanation:

Let the solution to

2x^2 + x -1 =0

x^2+ (1/2)x -(1/2)

are a and b

Hence a + b = -(1/2) ( minus the coefficient of x )

ab = -1/2 (the constant)

A. We want to have an equation where the roots are a +5 and b+5.

Therefore the sum of the roots is (a+5) + (b+5) = a+ b +10 =(-1/2) + 10 =19/2.

The product is (a+5)(b+5) =ab + 5(a+b) + 25 = (-1/2) + 5(-1/2) + 25 = 22.

So the equation is

x^2-(19/2)x + 22 =0

2x^2-19x + 44 =0

B. We want the roots to be 3a and 3b.

Hence (3a) + (3b) = 3(a+b) = 3(-1/2) =-3/2 and

(3a)(3b) = 9(ab) =9(-1/2)=-9/2.

So the equation is

x^2 +(3/2) x -9/2 = 0

2x^2 + 3x -9 =0.

4 0
3 years ago
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