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Svetlanka [38]
3 years ago
10

Multiply 3x^2-2x and 2x^2+3x-1

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0

Answer:

6x^{4} + 5x³ - 9x² + 2x

Step-by-step explanation:

Given

(3x² - 2x)(2x² + 3x - 1)

Each term in the second factor is multiplied by each term in the first factor, that is

= 3x²(2x² + 3x - 1) - 2x(2x² + 3x - 1) ← distribute both parenthesis

= 6x^{4} + 9x³ - 3x² - 4x³ - 6x² + 2x ← collect like terms

= 6x^{4} + 5x³ - 9x² + 2x

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3 years ago
Which of these ordered pairs is a solution to the linear inequality 3y - 2x > 8?
Tanzania [10]
For this case we have the following inequality:
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3 0
3 years ago
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8 0
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notka56 [123]

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Step-by-step explanation:


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