The formula for the monoprotic acid is taken as HA, reaction with base is as follows;
HA + NaOH ---> NaA + H₂O
Stoichiometry of acid to base is 1:1
At the neutralisation point, number of HA moles = number of base moles
Number of NaOH moles reacted = 0.100M / 1000 mL /L x 30.0 mL = 0.003 mol
Therefore number of HA moles reacted = 0.003 mol
the mass of acid 0.384 g
Therefore molar mass - 0.384 g/ 0.003 mol = 128 g/mol
THINK OF GUMMY BEARS IN A TEST TUBE AND IN THAT TEST TUBE THEIRS A SUBSTANCE ACID IT EX PLODS LOOK IT UP ON YOU TUBE
Answer:
10.52g KOH
Explanation:
250.0 ml X 1L/1000ml X 0.75 mol KOH/1L X 56.105gKOH/1 mol KOH =10.52g KOH
3K + AlCl3 --------> 3 KCl + Al
element compound compound element
This is single replacement (displacement) reaction.
