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Alchen [17]
3 years ago
8

What is the relationship between the concentration of particles in a solution and the solution’s vapor pressure? As solute conce

ntration increases, vapor pressure increases. As solute concentration increases, vapor pressure decreases. As the concentration of electrolytes increases, vapor pressure increases. However, as the concentration of nonelectrolytes increases, vapor pressure decreases. As the concentration of electrolytes increases, vapor pressure decreases. However, as the concentration of nonelectrolytes increases, vapor pressure increases.
Chemistry
2 answers:
OLEGan [10]3 years ago
7 0

Answer: B on egd

Explanation:

kap26 [50]3 years ago
5 0

Answer:

As solute concentration increases, vapor pressure decreases.  

Step-by-step explanation:

As solute concentration increases, the number of solute particles at the surface of the solution increases, so the number of <em>solvent </em>particles at the surface <em>decreases</em>.

Since there are fewer solvent particles available to evaporate from the surface, the vapour pressure decreases.

C. and D. are <em>wrong</em>. The vapour pressure depends <em>only</em> on the number of particles. It does not depend on the nature of the particles.

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What is the molarity of a solution prepared by dissolving 10.7 g NaI in 0.250 L?0.0714
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4 0
3 years ago
Read 2 more answers
1.
german

Order of metals from least reactive to most reactive: B <C <A <D

<h3>Further explanation</h3>

Reducing agents are substances that experience oxidation  

Oxidizing agents are substances that experience reduction

The metal activity series is expressed in voltaic series  

<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au  </em>

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent  

The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent

So that the metal located on the left can push the metal on the right in the redox reaction  

Let's analyze the statement in the problem

I. Only A, C and D react with 1 mol/L HCl to give H₂(e)

M + HCl ⇒ MCl + H₂(MCl : alkali, MCl₂ : alkaline earth)

A, C and D can react with 1 mol / L HCl, meaning metals A, C and D are located to the left of element H (more reactive), and B in the right of element H

II. When A is added to solutions of the other metal ions, metallic B and C are  formed but not D.

This means that metal A is more reactive than metals B and C, while D is more reactive than A, so metal D is the most reactive

3 0
3 years ago
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order = SrS > SrCl2 > RbCl > CsBr

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The ionic radii is also another factor to be considered, the more the distance between ions, the lesser the bond strength and the lesser the melting point.

from the options, in terms of ionic radii SrS > SrCl2 and RbCl > CsBr

also both SrS and SrCl2 have more charges on their ions compared to RbCl and CsBr and as such the arrangement of the highest melting point will be in the order SrS > SrCl2 > RbCl > CsBr.

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3 years ago
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