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2 years ago

How do changes in temperature affect the rate of a reaction?

1 answer:

8 0

Answer:An increase in temperature commonly will increase the rate of reaction. An growth in temperature will improve the common kinetic electricity of the reactant molecules.

Explanation:

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I have no idea pls help ty 11 points

Yanka [14]

Happy Holidays! :)

$\large\boxed{\text{Water.}}$

Looking at the information given in the description, the experiment is testing for the effects of the different salts on the growth of the plants.

This means that the type of salt is the independent variable, or the variable being manipulated and tested.

To ensure fair results, some parts of the experiment would need to be kept the same, which is the control. The only answer choice that makes sense in this instance is A. water.

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3 years ago

Read 2 more answers

Which TWO are most likely to form a compound?<br> C<br> Mg<br> S<br> Ar

lbvjy [14]

Answer is Mr and S as MgS ..

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3 years ago

What are 5 physical changes in matter

Gennadij [26K]

Answer:

cutting, bending, dissolving, freezing, and boiling

Explanation:

A physical change is a change in one or more physical properties of matter without any change in chemical properties. In other words, matter doesn't change into a different substance in a physical change. Examples of physical change include but are not limited to, from solid to liquid or from liquid to gas are also physical changes.

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2 years ago

NEED HELP FAST

andre [41]

Answer: im not writting a pharaphraph. Buuuuuuuuuuuut... explian the type of reaction then explanie how that type of reaction works.

Explanation:

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2 years ago

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In another experiment, a 0.150 M BF4^-(aq) solution is prepared by dissolving NaBF4(s) in distilled water. The BF4^-(aq) ions in

Ilia_Sergeevich [38]

Answer:

A) Forward rate = 1.1934 × 10^(-4) M/min

B) I disagree with the claim

Explanation:

A) We are told that [HF] reaches a constant value of 0.0174 M at equilibrium.

The reversible reaction given to us is;

BF4-(aq) +H20(l) → BF3OH-(aq) + HF(aq)

From this, we can see that the stoichiometric ratio is 1:1:1:1

Thus, concentration of [BF4-] is now;

[BF4-] = 0.150 - 0.0174

[BF4-] = 0.1326 M

From the rate law, we are told the forward rate is kf [BF4-].

We are given Kf = 9.00 × 10^(-4) /min

Thus;

Forward rate = 9.00 × 10^(-4) /min × (0.1326M)

Forward rate = 1.1934 × 10^(-4) M/min

(B) The student claims that the initial rate of the reverse reaction is equal to zero can't be true because at equilibrium, rates for the forward and reverse reactions are usually equal.

Thus, I disagree with the claim.

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2 years ago