Answer:
![q_{rxn}=-488.86\frac{kJ}{mol}](https://tex.z-dn.net/?f=q_%7Brxn%7D%3D-488.86%5Cfrac%7BkJ%7D%7Bmol%7D)
Explanation:
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In this case, since this calorimetry problems can by analyzed by figuring out that the heat lost due to the combustion of C6H12O6 is gained by the water and the calorimeter which undergo the mentioned temperature rise, we can write:
![Q_{rxn}=-(m_wC_w+C_c)(T_2-T_1)](https://tex.z-dn.net/?f=Q_%7Brxn%7D%3D-%28m_wC_w%2BC_c%29%28T_2-T_1%29)
Thus, by plugging in the given data, we obtain:
![Q_{rxn}=-(950.0g*4.184\frac{J}{g\°C} +933\frac{J}{\°C})(42.3\°C-35.0\°C)\\\\Q_{rxn}=-17.5kJ](https://tex.z-dn.net/?f=Q_%7Brxn%7D%3D-%28950.0g%2A4.184%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%20%2B933%5Cfrac%7BJ%7D%7B%5C%C2%B0C%7D%29%2842.3%5C%C2%B0C-35.0%5C%C2%B0C%29%5C%5C%5C%5CQ_%7Brxn%7D%3D-17.5kJ)
Next, we compute the moles of C6H12O6 by using its molar mass (180.18 g/mol) as shown below:
![n=6.45g*\frac{1mol}{180.18g} =0.0358mol](https://tex.z-dn.net/?f=n%3D6.45g%2A%5Cfrac%7B1mol%7D%7B180.18g%7D%20%3D0.0358mol)
Thus, the value for q of the reaction turns out:
![q_{rxn}=\frac{Q_{rxn}}{n} \\\\q_{rxn}=\frac{17.5kJ}{0.0358mol} \\\\q_{rxn}=-488.86\frac{kJ}{mol}](https://tex.z-dn.net/?f=q_%7Brxn%7D%3D%5Cfrac%7BQ_%7Brxn%7D%7D%7Bn%7D%20%5C%5C%5C%5Cq_%7Brxn%7D%3D%5Cfrac%7B17.5kJ%7D%7B0.0358mol%7D%20%5C%5C%5C%5Cq_%7Brxn%7D%3D-488.86%5Cfrac%7BkJ%7D%7Bmol%7D)
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The answer is b
Protons and neutrons are both in the nucleus
Electrons are outside the nucleus
<h3>ANSWER:</h3>
(C) KBr
<h3>EXPLANATION:</h3>
An ionic compound is made up of a metal and a nonmetal. K is a metal while bromine is a nonmetal. Thus K transfers its one electron to bromine in order to form an ionic compound.
Answer:
As we read from left to right across the periodic table atomic numbers are increased by one each of element.
Explanation:
As we move from left to right across the periodic table the atomic number is increased by one and the number of valance electron in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.