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olga_2 [115]
3 years ago
14

I really need help lol SOMEONE HELP ILL MARK YOU AS BRAINLIESTTT

Mathematics
1 answer:
V125BC [204]3 years ago
6 0

Answer:it would be the fourth one

Step-by-step explanation:

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Three vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.
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Given:

The three vertices of a parallelogram are (-3,8), (4,5), (2,-5).

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Solution:

Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).

We know that, diagonals of a parallelogram bisect each other. It means midpoints of both diagonals are same.

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Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Two diagonals of ABCD are AC and BD.

Midpoint of AC = Midpoint of BD

\left(\dfrac{-3+2}{2},\dfrac{8-5}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)

\left(\dfrac{-1}{2},\dfrac{3}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)

On comparing both sides, we get

\dfrac{4+a}{2}=\dfrac{-1}{2}

4+a=-1

a=-1-4

a=-5

And,

\dfrac{5+b}{2}=\dfrac{3}{2}

5+b=3

b=3-5

b=-2

Therefore, the coordinates of fourth vertex are (-5,-2).

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