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olga_2 [115]
2 years ago
14

I really need help lol SOMEONE HELP ILL MARK YOU AS BRAINLIESTTT

Mathematics
1 answer:
V125BC [204]2 years ago
6 0

Answer:it would be the fourth one

Step-by-step explanation:

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Makoto rolled a fair number cube 4 times and it landed on 6 every time. If he tosses the cube a fifth time, what is the probabil
sleet_krkn [62]
The probability will be 1/6
7 0
3 years ago
2. What is the x-value to the solution for the system of equations y = -5x - 9 and y = 2x<br> + 5.
pav-90 [236]

Answer:

The x-value is -2

Step-by-step explanation:

U can substitute any of the equations for y

-5x + (-9) = 2x + 5

-9 = 7x + 5

-14 = 7x

-2 = x

x = 2

7 0
2 years ago
I need the answers for these please
Luda [366]
11.p=-8, 17-8=9
12.y=11, 3*11=33+16=46
13.t=4, 4*4=16-14=2
14.x=9, -9x 9*8=82-9=72-9=62
15.z=4, 12*4=48-18=30
16.g=0, 4*0=0, 7+0=7
17.x=4, 9*4=36-24=-3
18.q=3, 18*3=48+2=50
19.c=2, 3*2=6-4.5=4.1
20.y=4, 9+4=13+4.8=17.4

8 0
3 years ago
"The product of eight and some number" can be written as:
Angelina_Jolie [31]
8n
Hope it helps, good luck
6 0
2 years ago
Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p
tankabanditka [31]

Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

- Mirror 1: D_1 = 8''

- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

                                           LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

                                           A ∝ D^2

- Hence,                              LGP ∝ D^2

- Now compare the two diameters given:

                                           LGP_1 ∝ (D_1)^2

                                           LGP ∝ (D_2)^2

- Take a ratio of both:

                           LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

                               LGP_1/LGP_2 ∝ (8)^2 / (6)^2

- Compute:             LGP_1/LGP_2 ∝ 16/9 ≅ 1.778 times more

6 0
3 years ago
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