1.Simplify.
-2{x}^{2}-4x+13+12{x}^{2}+2x-25−2x2−4x+13+12x2+2x−25
2.Collect like terms.
(-2{x}^{2}+12{x}^{2})+(-4x+2x)+(13-25)(−2x2+12x2)+(−4x+2x)+(13−25)
3.Simplify.
10{x}^{2}-2x-1210x2−2x−12
The answer is C and D
First we must make one side of the equation zero, so we subtract 7 on both sides of the equation, making the equation 9x^2 - 6x - 6 = 0
Then we will use the quadratic formula to find the answers.
using the Quadratic Formula where:
a = 9, b = -6, and c = -6
and the formula is 6 +- 
Your answer would be 31.04 m2
Answer:
Step-by-step explanation:
"When 200 gallons of oil were removed from a tank" algebraically looks like this:
V - 200.
"...the volume of oil left in the tank was 3/7 of the tank's capacity" algebraically looks like this:
3/7(V)
Therefore, the equation is
V - 200 = 3/7(V)
Begin by multiplying both sides by 7:
7(V - 200) = 3V and
7V - 1400 = 3V so
-1400 = -4V so
V = 350 gallons
That's if the volume of the oil in the tank was 3/7 of the tank's capacity.
For the other part of the problem, we set up the equation almost the same, except the 3/7 is a 1/2:
V - 200 = 1/2(V)
Multiplying both sides by 2 gives you
2(V - 200) = V and
2V - 400 = V so
-400 = -V so
V = 400
Answer: he should invest $16129 today.
Step-by-step explanation:
Let $P represent the initial amount that should be invested today. It means that principal,
P = $P
It would be compounded annually. This means that it would be compounded once in a year. So
n = 1
The rate at which the principal would be compounded is 7.6%. So
r = 7.6/100 = 0.076
The duration of the investment would be 6 years. So
t = 6
The formula for compound interest is
A = P(1+r/n)^nt
A = total amount in the account at the end of t years.
A = 25000
Therefore
25000 = P(1+0.076/1)^1×6
25000 = P(1.076)^6
25000 = 1.55P
P = 25000/1.55
P = $16129
