A hot pack contains 715g of water at 60 degrees Celsius. If the water cools to body temperature, how many kilocalories of heat c
1 answer:
<u>Answer:</u>
<em>49822 joules of heat can be transferred to ankle from heat bag. </em>
<u>Explanation:</u>
We know that average body temperature should be <em>37 degree centigrade </em>
Hot water bag has 715 grams of water present in it. Specific heat of 1 gram of water is 4.18 joules per gram per degree centigrade. 715 grams will have
The degree of water that is given is 60° hence specific heat becomes
<em>Specific heat of body at 37° centigrade will be = </em>
<em>The amount of heat that can be transferred from hot bag will be </em>
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Answer: The molecular formula will be
Explanation:
Mass of = 17.95 g
Mass of = 4.87 g
Molar mass of carbon dioxide = 44 g/mol
Molar mass of water = 18 g/mol
For calculating the mass of carbon:
In 44g of carbon dioxide, 12 g of carbon is contained.
So, in 17.95 g of carbon dioxide, = of carbon will be contained.
For calculating the mass of hydrogen:
In 18g of water, 2 g of hydrogen is contained.
So, in 4.87 g of water, = of hydrogen will be contained.
Mass of oxygen in the compound = (12.00) - (4.89+0.541) = 6.57 g
Mass of C = 4.89 g
Mass of H = 0.541 g
Mass of O = 6.57 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of H=
Moles of O=
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For H =
For O =
The ratio of C : H : O = 1: 1 : 1
Hence the empirical formula is .
Hence the empirical formula is
The empirical weight of = 1(12)+1(1)+1(16)= 29 g.
If 0.25 moles has mass of 44.0 g
Thus 1 mole has mass of =
Thus molecular mass is 176 g
Now we have to calculate the molecular formula.
The molecular formula will be=