1. First, let us define the width of the rectangle as w and the length as l.
2. Now, given that the length of the rectangle is 6 in. more than the width, we can write this out as:
l = w + 6
3. The formula for the perimeter of a rectangle is P = 2w + 2l. We know that the perimeter of the rectangle in the problem is 24 in. so we can rewrite this as:
24 = 2w + 2l
4. Given that we know that l = w + 6, we can substitute this into the formula for the perimeter above so that we will have only one variable to solve for. Thus:
24 = 2w + 2l
if l = w + 6, then: 24 = 2w + 2(w + 6)
24 = 2w + 2w + 12 (Expand 2(w + 6) )
24 = 4w + 12
12 = 4w (Subtract 12 from each side)
w = 12/4 (Divide each side by 4)
w = 3 in.
5. Now that we know that the width is 3 in., we can substitute this into our formula for length that we found in 2. :
l = w + 6
l = 3 + 6
l = 9 in.
6. Therefor the rectangle has a width of 3 in. and a length of 9 in.
Answer:
8.64 × 104
Step-by-step explanation:
Since 1 lap I every 6 minutes then 30\6 is 5 so the answer is 5 LAPS
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Population mean (μ) = 2.55
Population standard deviation (σ) = 0.5
Sample size (n) = 30
Sample mean (x) = 2.76
α = 0.05
STEP 1:
Stress score in general executive (s1)
Stress score in exercising executive (s2)
Null : s1 = s2
Alternative : s1 < s2
STEP 2:
Shape of distribution = normal
Population mean (μ) = 2.55
Population standard deviation (σ) = 0.5
Sample size (n) = 30
Sample mean (x) = 2.76
α = 0.05
Decision rule :
α = 0.05 which corresponds to a t score (t0) ;
df = n - 1 = 30 - 1= 30 at 0.05 = 1.699
If :
(Test statistic (t) > t0) ; reject the Null
(right tailed test)
Test statistic (t) :
(x - μ) / (σ/√n)
(2.76 - 2.55) / (0.5/√30)
0.21 / 0.0913
= 2.30
t > t0
2.30 > 1.699
t is more extreme than t0
Hence, reject the null at α = 0.05
