Assume a population of deer has a crude birth rate of 36 per 1,000/yr, a crude death rate of 20 per 1,000/yr, an immigration rat
1 answer:
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The answer is Rr and rr.
We know:
r - recessive allele
R - dominant allele
RR - dominant homozygote with red eyes
Rr - heterozygote with red eyes (since one dominant allele R can mask recessive allele r)
rr - recessive homozygote with sepia eyes
Heterozygote Rr can give to the offspring either dominant allele R or recessive allele r. Recessive homozygote rr can give to the offspring only recessive allele r (take a look at the uploaded image of Punnett square).
After crossing the parents:
Parents: Rr x rr
Offspring: Rr rr Rr rr
So:
2 out of 4 offspring will be with heterozygous with red eyes Rr: 2/4 = 0.5 = 50%
2 out of 4 offspring will be with homozygous with sepia eyes rr: 2/4 = 0.5 = 50%
We know:
r - recessive allele
R - dominant allele
RR - dominant homozygote with red eyes
Rr - heterozygote with red eyes (since one dominant allele R can mask recessive allele r)
rr - recessive homozygote with sepia eyes
Heterozygote Rr can give to the offspring either dominant allele R or recessive allele r. Recessive homozygote rr can give to the offspring only recessive allele r (take a look at the uploaded image of Punnett square).
After crossing the parents:
Parents: Rr x rr
Offspring: Rr rr Rr rr
So:
2 out of 4 offspring will be with heterozygous with red eyes Rr: 2/4 = 0.5 = 50%
2 out of 4 offspring will be with homozygous with sepia eyes rr: 2/4 = 0.5 = 50%