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3 years ago

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An aluminum alloy containing 48% aluminum is to be made by containing 30% and 60% alloys. How many pounds of the 60% alloy must

be added to 24 pounds of the 30% alloy to produce the desired aluminum alloy?

1 answer:

shusha [124]3 years ago

3 0

Answer:

36 pounds

Step-by-step explanation:

48% = 48/100 = 0.48

30% = 30/100 = 0.3

60% = 60/100 = 0.6

Let pounds of 60% alloy added = x

So, from the statement, we can write:

0.6x + 0.3(24) = 0.48(x + 24)

Note "x + 24" in total because we are adding "x" from 60% and "24" from 30% alloys.

Now, we have to solve the above equation for x:

$0.6x + 0.3(24) = 0.48(x + 24)\\0.6x+7.2=0.48x+11.52\\0.6x-0.48x=11.52-7.2\\0.12x=4.32\\x=\frac{4.32}{0.12}\\x=36$

Thus,

We would need 36 pounds added from 60% alloy

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Tems11 [23]

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$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

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The given problem is

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Convert the mixed numbers to improper fraction to obtain;

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$11 \times 2 \frac{7}{11}$

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