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3 years ago

A worker's earnings e are a function of the number of hours n worked at a rate of 8.75 per hour

1 answer:

3 0

E=8.75*n ............................................................................................................................................

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What is the following quotient 9+sqrt 2/4-sqrt 7

babunello [35]

9 + √2 / 4 - √7

Multiply the numerator and denominator by the conjugate.

Exact form:

(36 + 9√ 7 + 4√2 + √14) / 9

about 7.69

:)))

8 0

3 years ago

Read 2 more answers

The lines y1 = 2x - 6, y2 = -3x + 4, y3 = -1/2x + 4 are the sides of a right triangle. Find the perimeter and area of the triang

sergiy2304 [10]

The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

<h3>Perimeter and area of the triangle giving the equation of a line</h3>

First we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

From the given equation of the lines, the points of intersection of the line are (x₁, y₁) = (- 0.4, 5.2), (x₂, y₂) = (-0.8, 4.4) and (x₃, y₃) = (0, 4)

For the base

b² = c² -a²

b = √(-0.8)² + (4 - 4.4)²

b = 2√5 / 5

For the height

h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²

height = 2√5 / 5

For the hypotenuse

r = √2 · b

r = 2√10 / 5

<h3>Determine the Perimeter and area</h3>

Perimeter = s1+s2+s3

Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5

Perimeter = (2√10 + 4√5) / 5 units

area = 1/2* base * height

A = 0.5 · (2√5 / 5) · (2√5 / 5)

A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/21511715

#SPJ1

8 0

2 years ago

Help what is 1/3 to decimal

sleet_krkn [62]

Hey there! I'm happy to help!

To turn a fraction into a decimal, you simply divide the numerator by the denominator!

1÷3=0.3333333333.... (the 3s never end!)

Have a wonderful day! :D

4 0

3 years ago

Plzzzzzzzzzzzzzzz<br><br>evaluate 4x(4+(2^6x2^-3))

Scilla [17]

11. Factoring and solving equations - A. Factor- 1. Factor 3x2 + 6x if possible. Look for monomial (single-term) factors first; 3 is a factor of both 3x2 and 6x and so is x . Factor them out to get 3x2 + 6x = 3(x2 + 2x1 = 3x(x+ 2) . 2. Factor x2 + x - 6 if possible. Here we have no common monomial factors. To get the x2 term we'll have the form (x +-)(x +-) . Since (x+A)(x+B) = x2 + (A+B)x + AB , we need two numbers A and B whose sum is 1 and whose product is -6 . Integer possibilities that will give a product of -6 are -6 and 1, 6 and -1, -3 and 2, 3 and -2. The only pair whose sum is 1 is (3 and -2) , so the factorization is x2 + x - 6 = (x+3)(x-2) . 3. Factor 4x2 - 3x - 10 if possible. Because of the 4x2 term the factored form wli be either (4x+A)(x +B) or (2x+A)(2x+B) . Because of the -10 the integer possibilities for the pair A, B are 10 and -1 , -10 and 1 , 5 and -2 . -5 and 2 , plus each of these in reversed order. Check the various possibilities by trial and error. It may help to write out the expansions (4x + A)(x+ B) = 4x2 + (4B+A)x + A8 1 trying to get -3 here (2x+A)(2x+B) = 4x2 + (2B+ 2A)x + AB Trial and error gives the factorization 4x2 - 3x - 10 - (4x+5)(x- 2) . 4. Difference of two squares. Since (A + B)(A - B) = - B~ , any expression of the form A' - B' can be factored. Note that A and B might be anything at all. Examples: 9x2 - 16 = (3x1' - 4' = (3x +4)(3x - 4) x2 - 29 = x2 - (my)* = (x+ JTy)(x- my)

8 0

3 years ago

Find the GCF of the terms of the polynomial. 24x^5 + 32x^3 – 12x

FromTheMoon [43]

Answer:

$GCF_{Numerical}$ $= 4$ $GCF_{Variable}$ $= x$