Answer:
2.12×10^-2hour
Explanation:
Acceleration is defined as the change in velocity of a body with respect to time.
Using one of the equations of motion:
S = ut + 1/2at²
Where S is the distance traveled by the airplane
u is the initial velocity
a is its acceleration
t is the time of travel
Given a = 1.2×104 km/h²
u = 60km/hr
t= ?
S = 4km
Substituting the values given into the formula to get 't'
4 = 60t+1/2(1.2×10⁴)t²
4 = 60t+0.6×10⁴t²
0.6×10⁴t²+60t-4= 0
Factorizing the quadratic equation
t = -b±√b²-4ac/2a
Where a= 6000 b = 60 c = -4
t = -60±√60²-4(6000)(-4)/2(6000)
t = -60±√3600+96000/12000
t = -60±√99600/12000
t = -60±315.6/12000
t = -60+315.6/12000
t= 255.6/12000
t = 0.0212hour
t = 2.12×10^-2hour
Answer:
A- The ball has both kinetic and potential energy,
Explanation:
kinetic energy by virtue of its motion.
potential energy by virtue of its position. (It could roll off the edge of the tabel and convert gravity potential energy to kinetic energy)
<span>A partial repeal occurs when a specified part or provision of a previous Act is repealed but other provisions remain in force. </span>
Answer:
The SI unit of force is the newton, symbol N. The base units relevant to force are: The metre, unit of length — symbol m. The kilogram, unit of mass — symbol kg.
The formula for the fundamental frequency for an open tube at one end is : F = nV/4L the integer n = 3 which describe the frequency 450 hertz and length of tube L = 0.6m approximately
<h3>What is frequency?</h3>
Frequency of the object is defined as the number of cycles attend in a second .
Given that a tube is open only at one end. And a certain harmonic produced by the tube has a frequency of 450 Hz. The next higher harmonic has a frequency of 750 Hz. The formula for the fundamental frequency for an open tube at one end is :
That is, 1st harmonic
2nd harmonic =
3rd harmonic =
The general formula can therefore be
For the first harmonic in the question,
make 4L the subject of the formula
The next higher harmonic will be
make 4L the subject of the formula
Equate the two 4L
cross multiply
collect the likes term
n = 3
Given that the speed of sound in air is 343 m/s, The length of the tube can be calculate by using the same formula.
4L = 2.28
L = 0.57 m
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