Question

2. A force of 156 N acts on a 7.3-kg bowling ball for 0.40 s.

Answer 1

Answer:

$62.4N\cdot s$

Explanation:

The change in momentum of the ball is equal to the impulse exerted on it, therefore:

$\Delta p = I = F \Delta t$

where

$\Delta p$ is the change in momentum

F is the average force exerted on the ball

$\Delta t$ is the time during which the force is applied

In this problem,

F = 156 N

$\Delta t = 0.40 s$

So, the change in momentum of the ball is

$\Delta p =(156)(0.40)=62.4N\cdot s$