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Molodets [167]
3 years ago
14

Help figuring out what to do on here

Mathematics
1 answer:
Andreyy893 years ago
7 0
You got to use the formula provided to solve the problem! Have confidence! you can do it!
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At a baseball game, the ratio of Barons fans to Blue Sox fans is 8 : 3. If you know that at least 22,000 people are attending th
Ahat [919]
11/22,000 = 3/x
11x=66,000
x=6,000 (3/11 of 22,000)
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6 0
3 years ago
What is the formula for 3cm, 5cm, and 4cm (3cm being the height and the 4 the base) and its a right triangle
Feliz [49]

Answer:

No se perdon nesesito puntos

6 0
3 years ago
30 PTS!!! ANYONE GOOD AT MATH PLS HELP!
siniylev [52]

Answer:

\frac{2}{\sqrt{5} }

Step-by-step explanation:

To solve this, all we need to do is draw a triangle.  

From the arctan(2) we can deduce that tan(x)=\frac{2}{1}

From that, we can draw our triangle as we know that tan(x) is the opposite side over the adjacent side. Attached is that triangle. Through the Pythagorean Theorem, we can find that the hypotenuse of this right triangle is  \sqrt{5}

Now all we need to do is take the sin of this triangle, which is the opposite side over the hypotenuse

This gives us the value of \frac{2}{\sqrt{5} } which is our answer.

8 0
3 years ago
Please Explain/Show Your Work, for each part of the question! Thank You!
mina [271]

Answer:

1. The graph represents a proportional relationship

2. 70,000 miles

Step-by-step explanation:

1. The graph represents a proportional relationship since the graph line is straight and begins at the origin.

2. Plot 5.5 hours on the graph and it'll give you 70,000 miles

3 0
3 years ago
Evaluate the summation of negative 2 n minus 3, from n equals 2 to 10..
Alisiya [41]
\bf \sum\limits_{n=2}^{10}~-2n-3

so, let's first change the bounds from 1 to 9, so we'll be dropping the indices by 1, in order to do the variable "n".

however, let's use a variable hmmm say "k", where "k" is the value of "n" beginning at 1, thus k = n - 1.

however, if k = n - 1, then k + 1 = n.  So let's use those fellows then,

\bf \sum\limits_{n=2}^{10}~-2n-3\qquad 
\begin{cases}
k=n-1\\
k+1=n
\end{cases}\implies \sum\limits_{k=1}^{9}~-2\stackrel{n}{(k+1)}-3
\\\\\\
\sum\limits_{k=1}^{9}~-2k-2-3\implies \sum\limits_{k=1}^{9}~-2k-5\implies \sum\limits_{k=1}^{9}~-2k-\sum\limits_{k=1}^{9}~5
\\\\\\
-2\sum\limits_{k=1}^{9}~k-\sum\limits_{k=1}^{9}~5\implies -2\left( \cfrac{9(9+1)}{2} \right)\qquad -\qquad (9\cdot 5)
\\\\\\
-2(45)-45\implies -90-45\implies -135
5 0
3 years ago
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