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Lena [83]
3 years ago
11

Solve the inequality 3x/2- 2 > 7

Mathematics
2 answers:
In-s [12.5K]3 years ago
4 0

Answer:

<h3>NO SOLUTIONS</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate x on one side of the equation.

3x/2-2>7

3x/2-2-7>7-7 (First, subtract 7 from both sides.)

7-7 (Solve.)

7-7=0

3x/2-2-7>0

3x/2-2*0-7*0>0*0 (Then, multiply 0 from both sides.)

0*0 (Solve & simplify.)

0*0=0 (undefined & no solutions)

In conclusion, there are no solutions.

IRISSAK [1]3 years ago
3 0

Answer:

x>6

Step-by-step explanation:

3x/2-2>7

     +2  +2

3x/2>9

2/3 x 3x/2>9/1 x 2/3

        x>6

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find the particular solution to the exact differentiable equation dy/dx=(2e^x)-cosx passing through the point (0,3)
lozanna [386]

Answer:

y = 2eˣ - sin x + 1  

Step-by-step explanation:

dy/dx = 2eˣ - cos x

(0, 3)

Integrate dy/dx to find the original function.

  • y = 2eˣ - sin x + C

Solve for C by substituting the point given.

  • 3 = 2e⁰ - sin(0) + C
  • 3 = 2 - 0 + C
  • 1 = C

Now we can substitute C into the original function.

  • y = 2eˣ - sin x + 1  

This is the particular, or explicit, solution to the differentiable equation.

7 0
3 years ago
What is the measure of angle RSL if it is (9x+27)° and angle BSA is (6x+66)°
Shalnov [3]

Answer:

Assume:

(angle) RSB and angle (LSA) = D

and (line) ASR and (line) LSB is striaght then

(9x +27) + D = 180

(6x + 66) + D = 180

9x + D = 153

6x + D = 114

substitute

6x + D = 114

D = 114 - 6 x

9x + (114 - 6x) =153

3x = 39

x = 13

D = 114 - 6(13)

D=36


Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
Monifer used substitution to solve this system of equations. Which equation could be the result of her first step? 3a +b=225 b=a
weeeeeb [17]
3a + a - 15 = 225 . your substituting b(a-15) into the first equation. <span />
6 0
3 years ago
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The following data show the weight, in ounces, of 10 different bags of candy:
LuckyWell [14K]
B) is correct; on average, each bag of candy has a weight that is 2.6 oz different than the mean weight of 5 oz.

To find the mean absolute deviation, we first find the mean.  Find the sum of the data points and divide by the number of data points (without the outlier, 21, in it):
(10+3+7+3+4+6+10+1+2+4)/10 = 50/10 = 5

Now we find the difference between each data point and the mean, take its absolute value, and find their sum:
|10-5|+|3-5|+|7-5|+|3-5|+|4-5|+|6-5|+|10-5|+|1-5|+|2-5|+|4-5| =
5+2+2+2+1+1+5+4+3+1 = 26

We now divide this by the number of data points:
26/10 = 2.6

This is a measure of how much each bag of candy varies from the mean.
4 0
3 years ago
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A company that rents small moving trucks wants to purchase 25 trucks with a combined capacity of 28,000 cubic feet. Three differ
pickupchik [31]

Answer:

We have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks

Step-by-step explanation:

Let the number of 10-foot truck with a capacity of 350 cubic feet purchased=a

Let the number of 14-foot truck with a capacity of 700 cubic feet purchased=b

Let the number of 24-foot truck with a capacity of 1,400 cubic feet purchased=c

The company wants to purchase 25 trucks, therefore.

  • a+b+c=25

Furthermore, the combined capacity of the trucks is 28,000 cubic feet.

  • 350a+700b+1400c=28000

Since the number of equations is less than the number of variables, you can not use a matrix equation to solve this problem.  The solution is most easily found using an augmented matrix.  

The augmented matrix is presented below:  

\left[\begin{array}{ccc|c}1&1&1&25\\350&700&1400&28000\end{array}\right]

Using the calculator, the reduced row echelon form is:

\left[\begin{array}{ccc|c}1&0&-2&-30\\0&1&3&55\end{array}\right]

where  

a- 2c=-30 means a =2c-30

b+3c=55 means b= 55-3c

We alter the value of c as long as neither a nor b becomes negative. Suitable values for c are 15, 16, 17, and 18:

\left|\begin{array}{|c||c||c|}a=2c-30&b=55-3c&c\\0&10&15\\2&7&16\\4&4&17\\6&1&18\end{array}\right|

We can easily  verify that, for each solution, the number of trucks adds up to 25 and the fleet capacity is 28,000 cubic feet.

We therefore have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks
4 0
3 years ago
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