3 years ago

What is the shape of the horizontal cross section of the

Mathematics

2 answers:

GuDViN [60]3 years ago

6 0

Answer: Pentagon

Step-by-step explanation:

otez555 [7]3 years ago

6 0

Answer:

Pentagon

Step-by-step explanation:

I answered this on ED 2020

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Harlamova29_29 [7]

Answer:

(Z + 2•)

Step-by-step explanation:

5 0

3 years ago

Find the perimeter of a quadrilateral with vertices at C (-1, 2), D (-2, -1), E (2, -2), and F (1, 1). Round your answer to the

babymother [125]

Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

$d=\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2} }$

DC:

D(-2,-1) C(-1,2)

$d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2} } \\d=\sqrt{10} =3.16$

CF:

C(-1,2) F(1,1)

$d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2} } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24$

F(1,1) E(2,-2)

$d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16$

E(2,-2) D(-2,-1)

$d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2} } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\$

3.16+2.24+3.16+4.12= 12.68

4 0

3 years ago

Identify the equation of the circle D with center D(−8,−1) and radius 3.

REY [17]

Answer:

(h+8)^2 + ( y +1)^2 = 9

Step-by-step explanation:

The equation of a circle can be written as

(x-h) ^2 +(y-k) ^2 = r^2

where (h,k) is the center and r is the radius

(h- -8)^2 + ( y - -1)^2 = 3^2

(h+8)^2 + ( y +1)^2 = 3^2

(h+8)^2 + ( y +1)^2 = 9

8 0

3 years ago

Read 2 more answers

What is 6+(-7) Please Please Please Please

kherson [118]

The answer would be -1

8 0

3 years ago

Write an equivalent expression for the expression shown below: a/3 + a/3 + a/3

iris [78.8K]

Answer:

3 (a/3) = a

Step-by-step explanation:

a/3 + a/3 + a/3

3 times a/3

the 3's cancel each other out

Keep up the good work! =)

3 0

3 years ago