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svp [43]
2 years ago
10

Determine the point estimate of the population mean for the confidence interval of (15, 32). Enter up to 1 decimal place. Point

estimate μ =
Mathematics
1 answer:
netineya [11]2 years ago
6 0

Answer:

The point estimate of the population mean for the confidence interval of (15,32) is 23.5

Step-by-step explanation:

We are given the following information in the question:

Confidence interval for population mean is (15, 32).

We have to find the point estimate for population mean.

Formula:

\mu = \displaystyle\frac{\mu_1+\mu_2}{2} = \frac{15+32}{2} = 23.5

The point estimate of the population mean for the confidence interval of (15, 32) is 23.5

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Last year 12 records in his collection now he has 15 records what is his percent increase of his Collection
Nesterboy [21]

Given that,

Last year record = 12

This year record = 15.

To find,

The percent increase of his Collection.

Solution,

The percent increase in his collection is given by :

\%=\dfrac{\text{final collection-initial collection}}{\text{initial collection}}\times 100\\\\=\dfrac{15-12}{12}\times 100\\\\=25\%

So, the percent increase of his collection is 25%.

3 0
3 years ago
In a 3-digit number, the hundreds digit is four more than the ones digit and the tens digit is twice the hundreds digit. If the
AVprozaik [17]
If the ones digit is "d", the number is (d+4)(2(d+4))(d), and the sum of digits is 4d+12 = 12. Then d=0.

The number is 480.
8 0
2 years ago
6(1 + 3R) = 2(10R - 9) -4R
Damm [24]

Answer:

R=-12

Step-by-step explanation:

6(1 + 3R) = 2(10R - 9) -4R

Distribute 6 through the parentheses

6+18R=2(10R-9)-4R

Distribute 2 through the parentheses

6+18R=20R-18-4R

Collect like terms

6+18R=16R-18

Move the variable to the left-hand side and change its sign

6+18R-16R=-18

Move the constant to the right-hand side and change its sign

18R-16R=-18-6

Collect like terms

2R=-18-6

Calculate the difference

2R=-24

Divide both sides of the equation by 2

R=-12

if you'd make me brainliest that'd be great, if not its ok as well! I hope this helped!!!

5 0
3 years ago
Can someone help me with this?
Vinil7 [7]
U can refer to the picture that I’ve attach below

8 0
1 year ago
There are 42 sixth-grade students and 60 fifth grade students. The students will be put in to the largest possible equal groups
scoundrel [369]

Answer:51 Groups

Step-by-step explanation:

60 students + 42 students = 102

102 divided by 2 = 51 Total groups.

5 0
3 years ago
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