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3 years ago

Can u pls help me with this question asap

Mathematics

2 answers:

Vlad [161]3 years ago

4 0

Answer:

Step-by-step explanation:

strojnjashka [21]3 years ago

3 0

Answer:

0.0025

Step-by-step explanation:

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Simplify: 3(14 - |-10 + 31) - 18 - 212 please provide a step by step explanation (:

jeka94

Answer:

Step-by-step explanation:

3(14║-10+3║)-║8-2║^2=3(14-║-7║)-║8-2║^2=3(14-7)-6^2=3(7)-36=21-36=-15

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2 years ago

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HELP ASAP I WILL GIVW YOU BRAINLIEST!!!!!!

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Their beliefs over who should have succeeded the Prophet Muhammad is the key theological difference between the two. Sunnis also have a less elaborate religious hierarchy than Shiites have, and the two sects' interpretation of Islam's schools of law is different

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2 years ago

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What is the mean? If the answer is a decimal, round it to the nearest tenth.

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Round out to the nearest 10th say 5 it would stay 5 unlike 8 would round to 10

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3 years ago

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A simulation was conducted using 10 fair six-sided dice, where the faces were numbered 1 through 6. respectively. All 10 dice we

kompoz [17]

Answer:

C) a sample distribution of a sample mean with n = 10

$\mu_{{\overline}{X}} = 3.5$

and $\sigma_{{\overline}{Y}} = 0.38$

Step-by-step explanation:

Here, the random experiment is rolling 10, 6 faced (with faces numbered from 1 to 6) fair dice and recording the average of the numbers which comes up and the experiment is repeated 20 times.So, here sample size, n = 20 .

Let,

$X_{ij}$ = The number which comes up on the ith die on the jth trial.

∀ i = 1(1)10 and j = 1(1)20

Then,

$E(X_{ij})$ = $\frac {1 + 2 + 3 + 4 + 5 + 6}{6}$

= 3.5 ∀ i = 1(1)10 and j = 1(1)20

and,

$E(X^{2}_{ij}$ = $\frac {1^{2} + 2^{2} + 3^{2} + 4^{2} + 5^{2} + 6^{2}}{6}$

= $\frac {1 + 4 + 9 + 16 + 25 + 36}{6}$

= $\frac {91}{6}$

$\simeq$ 15.166667

so, $Var(X_{ij}$ = $(E(X^{2}_{ij} - {(E(X_{ij})}^{2})$

$\simeq 15.166667 - 3.5^{2}$

= 2.91667

and $\sigma_{X_{ij}}$ = $\sqrt {2.91667}[/tex [tex]\simeq 1.7078261036$

Now we get that,

$Y_{j} = \frac {\sum_{j = 1}^{20}X_{ij}}{20}$

We get that $Y_{j}'s$ are iid RV's ∀ j = 1(1)20

Let, ${\overline}{Y} = \frac {\sum_{j = 1}^{20}Y_{j}}{20}$

So, we get that $E({\overline}{Y}) = E(Y_{j})$

= $E(X_{ij}$ for any i = 1(1)10

= 3.5

and,

$\sigma_{({\overline}{Y})} = \frac {\sigma_{Y_{j}}}{\sqrt {20}} = \frac {\sigma_{X_{ij}}}{\sqrt {20}} = \frac {1.7078261036}{\sqrt {20}} [tex]\simeq 0.38$