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tino4ka555 [31]
3 years ago
6

Find the roots x2 + 4x + 5 = 0

Mathematics
2 answers:
aev [14]3 years ago
8 0

Step-by-step explanation:

x {}^{2} + 4x + 5 \\ x {}^{2}  + 5x - x + 5 = 0 \\ x(x + 5) - 1(x + 5) = 0 \\ (x - 1)(x + 5)  = 0 \\ x - 1 = 0 \:  \:  \:  \:  \:  \:  \: x + 5 = 0 \\ x = 1 \:  \:  \:  \:  \: x =  - 5

Evgen [1.6K]3 years ago
3 0

Answer:-5/6

Step-by-step explanation:

x*2+4x+5=0

add similar elements: 2x+4x=6x.

6x+5=0

Subtract 5 from both sides.

6x+5-5=0-5.

simplify.

6x=-5

divide both sides by 6

6x/6=-5/6

answer

-5/6

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Paladinen [302]

Step-by-step explanation:

4 is the A or Ampltiude

To find the period set it equal to 2 pi/B

\frac{2\pi}{b}  =  \frac{6}{1}

\frac{b}{2\pi}  =  \frac{1}{6}

b=

\frac{2\pi}{6}

b=

\frac{\pi}{3}

There is no phase shift

The midline or d or vertical shift is 1.

Our equation for 8 is

4 \sin( \frac{\pi}{6} x)  + 1

9.Use sin function. The a value is 2 or -2 your choice.

Set up the period equal to the equation

\frac{2\pi}{b}  =  \frac{\pi}{3}

\frac{b}{2\pi}  =  \frac{3}{\pi}

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6 0
2 years ago
What is the square root of 144
dlinn [17]

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12

Step-by-step explanation:

12x12 is 144

3 0
3 years ago
Please answer asap!!!!!
kherson [118]

Step-by-step explanation:

The equation of a circle can be the expanded form of

\large \text{$(x-a)^2+(y-b)^2=r^2$}(x−a)

2

+(y−b)

2

=r

2

where rr is the radius of the circle, (a,\ b)(a, b) is the center of the circle, and (x,\ y)(x, y) is a point on the circle.

Here, the equation of the circle is,

\begin{gathered}\begin{aligned}&x^2+y^2+10x-4y-20&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4-49&=&\ \ 0\\ \\ \Longrightarrow\ \ &x^2+y^2+10x-4y+25+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &x^2+10x+25+y^2-4y+4&=&\ \ 49\\ \\ \Longrightarrow\ \ &(x+5)^2+(y-2)^2&=&\ \ 7^2\end{aligned}\end{gathered}

⟹

⟹

⟹

⟹

x

2

+y

2

+10x−4y−20

x

2

+y

2

+10x−4y+25+4−49

x

2

+y

2

+10x−4y+25+4

x

2

+10x+25+y

2

−4y+4

(x+5)

2

+(y−2)

2

=

=

=

=

=

0

0

49

49

7

2

From this, we get two things:

\begin{gathered}\begin{aligned}1.&\ \ \textsf{Center of the circle is $(-5,\ 2)$.}\\ \\ 2.&\ \ \textsf{Radius of the circle is $\bold{7}$ units. }\end{aligned}\end{gathered}

1.

2.

Center of the circle is (−5, 2).

Radius of the circle is 7 units.

Hence the radius is 7 units.

4 0
2 years ago
Find the inverse of the given function.
kodGreya [7K]

For this case we must find the inverse of the following function:

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We follow the steps below:

Replace f(x) with y:

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We exchange the variables:

x = - \frac {1} {2} \sqrt {y + 3}

We solve for "y":

- \frac {1} {2} \sqrt {y + 3} = x

Multiply by -2 on both sides of the equation:

\sqrt {y + 3} = - 2x

We raise both sides of the equation to the square to eliminate the radical:

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We subtract 3 from both sides of the equation:

y = 4x ^ 2-3

We change y by f ^ {- 1} (x):

f ^ {- 1} (x) = 4x ^ 2-3

Answer:f ^ {- 1} (x) = 4x ^ 2-3

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