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tino4ka555 [31]
3 years ago
6

Find the roots x2 + 4x + 5 = 0

Mathematics
2 answers:
aev [14]3 years ago
8 0

Step-by-step explanation:

x {}^{2} + 4x + 5 \\ x {}^{2}  + 5x - x + 5 = 0 \\ x(x + 5) - 1(x + 5) = 0 \\ (x - 1)(x + 5)  = 0 \\ x - 1 = 0 \:  \:  \:  \:  \:  \:  \: x + 5 = 0 \\ x = 1 \:  \:  \:  \:  \: x =  - 5

Evgen [1.6K]3 years ago
3 0

Answer:-5/6

Step-by-step explanation:

x*2+4x+5=0

add similar elements: 2x+4x=6x.

6x+5=0

Subtract 5 from both sides.

6x+5-5=0-5.

simplify.

6x=-5

divide both sides by 6

6x/6=-5/6

answer

-5/6

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A rectangle with a perimeter of 19m^2+2m-10 and a width of m^2 write an expression for the lenght
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Answer: \frac{17}{2}m^2+m-5

Step-by-step explanation:

By definition, the perimeter of a rectangle is:

P=2l+2w

Where "l" is the lenght and "w" is the width.

If you solve for "l":

P-2w=2l\\\\l=\frac{P-2w}{2}

In this case, you know that the following expression represents  the perimeter of the rectangle:

19m^2+2m-10

And the width of that rectanle is represented wih this expression:

m^2

Therefore, based on the explained above, you can conclude that the lenght  of that rectangle is given  by:

\frac{19m^2+2m-10-2(m^2)}{2}

Finally, simplifying the expression, you get:

=\frac{17m^2+2m-10}{2}=\frac{17}{2}m^2+m-5

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4 years ago
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Pani-rosa [81]
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