$6c^2d^{-3}\ \times\ 3c^3d^{-4}=6\cdot3\cdot c^{2+3}d^{-3+(-4)}=18c^5d^{-7}=\frac{18c^5}{d^7}$

$\frac{-16p^6q^5}{20q^7}=-\frac{16}{20}p^6q^{5-7}=-\frac{4}{5}p^6q^{-2}=-\frac{4p^5}{5q^2}$

8 0

3 years ago

Read 2 more answers

I NEED HELP ASAP!!!

BlackZzzverrR [31]

Answer:

The number that would go in the blank to get a perfect square trinomial is 18

Step-by-step explanation:

The middle term can always be found by taking twice of the square root of the final term.

2 * √81 = 18

5 0

3 years ago

Seven more than double a number one is equal to five less than triple that number. What is that number?

Inga [223]

Answer:

$-\frac{2}{5}$

Step-by-step explanation:

$7+2n=5-3n$

$2n+3n=5-7\\5n=-2\\n=-\frac{2}{5}$

6 0

3 years ago