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3 years ago

Angelina makes 70% of her free throws. What is the probability tha she will make her next two free throws?

Mathematics

1 answer:

Vesna [10]3 years ago

6 0

15 % on her next free throws because a percent is always out of a 100. leftover is 30 half of 30 is 15 do it is 15%

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Mario’s car has run out of gasoline. He walks 16 km west and then 12 km south looking for a gasoline station. If he is now h km

Masteriza [31]

Answer:

h = 20 km

Step-by-step explanation:

Mario's path forms a right triangle with legs 16 km and 12 km and hypotenuse h. Let's use the Pythagorean Theorem (a² + b² = c²) to solve for h.

16² + 12² = h²

256 + 144 = h²

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h = 20 km

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4 years ago

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The model shows,Maya, how to plant flowers in her garden.

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3 years ago

A triangle has two sides of lengths 7 and 9. What value could the length of

Temka [501]

Answer:

5, 13, 10, 8

Step-by-step explanation:

hello, so for this question keep in mind the triangle inequality theorem which states- a side must be smaller than the sum of the other two sides.

go through each of the choices.

a. 5+7=12 12>9

b.2+7=9 9>9 this cant be the answer since 9 is equal to nine, not greater than,

c. 13+7=20 20>9

d.10+7=17 17>9

e.8+7=15 15>9

f.22+7=29 29>9 although 29 is greater than 9, we also have to keep in mind that the other 2 sides must also be greater than the other side. so try 7+9= 16. 16 isnt greater than 22 so it can’t be one of the answers.

hope this helped :)

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4 years ago

Use the given transformation to evaluate the integral. (15x + 15y) dA R , where R is the parallelogram with vertices (−1, 4), (1

MA_775_DIABLO [31]

Answer:

$\int_R 15x+15y dA = \frac{8}{16875}$

Step-by-step explanation:

Recall the following: x = 15u+15v, y = -60u+15v. So, x-y = 75u. Then u = (x-y)/75. 4x+y = 75v. Then v = (4x+y)/75.

We will see how this transformation maps the region R to a new region in the u-v domain. To do so, we will see where the transformation maps the vertices of the region.

(-1,4) -> ((-1-4)/75,(4(-1)+4)/75) = (-1/15, 0)

(1,-4)->(1/15,0)

(3,-2)->(1/15,2/15)

(1,6)->(-1/15,2/15)

That is, the new region in the u-v domain is a rectangle where $\frac{-1}{15}\leq u \leq \frac{1}{15}, 0\leq v \leq \frac{2}{15}$ .

We will calculate the jacobian of the change variables. That is

$\left |\begin{matrix} \frac{du}{dx}& \frac{du}{dy}\\ \frac{dv}{dx}& \frac{dv}{dy}\end{matrix}\right|$ (we are calculating the determinant of this matrix). The matrix is

$\left |\begin{matrix} \frac{1}{75}& \frac{-1}{75}\\ \frac{4}{75}& \frac{1}{75}\end{matrix}\right|=(\frac{1}{75^2})(1+4) = \frac{1}{15\cdot 75}$ (the in-between calculations are omitted).

We will, finally, do the calculations.

Recall that

$15x+15y = 15(15u+15v) + 15(-60u+15v) = (15^2-15\cdot 60 )u+2\cdot 15^2v = 15^2(-3)u+2\cdot 15^2 v$

We will use the change of variables theorem. So,

$\int_R 15x+15y dA = \int_{\frac{-1}{15}}^{\frac{1}{15}}\int_{0}^{\frac{2}{15}} 15^2(-3)u+2\cdot 15^2 v \cdot (\frac{1}{15^2\cdot 5}) dv du = \int_{\frac{-1}{15}}^{\frac{1}{15}}\int_{0}^{\frac{2}{15}}\frac{-3}{5}u+\frac{2}{5}v dvdu$

This si because we are expressing the original integral in the new variables. We must multiply by the jacobian to guarantee that the change of variables doesn't affect the value of the integral. Then,

$\int_{\frac{-1}{15}}^{\frac{1}{15}}\int_{0}^{\frac{2}{15}}\frac{-3}{5}u+\frac{2}{5}v dvdu = \int_{\frac{-1}{15}}^{\frac{1}{15}}\frac{-3}{5}u\cdot \frac{2}{15} + \frac{2}{5}\cdot \left.\frac{v^2}{2}\right|_{0}^{\frac{2}{15}}du = \frac{-3}{5}\left.\frac{u^2}{2}\right|_{\frac{-1}{15}}^{\frac{1}{15}}\cdot \frac{2}{15} + \frac{2}{5}\cdot \left.\frac{v^2}{2}\right|_{0}^{\frac{2}{15}} = \frac{8}{16875}$

5 0

4 years ago

If the value of "y" varies directly with "X"

Svetradugi [14.3K]

Answer:

x : 3 :: y : -1

9 : 3 :: y : -1

3y = -9

y = -3

6 0

3 years ago