The digit in the hundred thousands place is the 2
Answer:
Not probabillity of picking a green marble is 80%
Step-by-step explanation:
Answer: 
<u>Step-by-step explanation:</u>
The general form of a sin/cos function is: y = A sin/cos (Bx-C) + D where the period (P) = 2π ÷ B
In the given function,
→ 
Half of that period is: 
Calculate the period for each of the options to find a match:

Let "a" and "b" represent the values of the first and second purchases, respectively.
0.40*(original price of "a") = $10
(original price of "a") = $10/0.40 = $25.00 . . . . divide by 0.40 and evaluate
a = (original price of "a") - $10 . . . . . . Julia paid the price after the discount
a = $25.00 -10.00 = $15.00
At the other store,
$29 = 0.58b
$29/0.58 = b = $50 . . . . . . . divide by the coefficient of b and evaluate
Then Julia's total spending is
a + b = $15.00 +50.00 = $65.00
Julia spent $65 in all at the two stores.
Answer:
The answer is, "The image will be in Quadrant II"
Step-by-step explanation:
When is comes to rotating something 180, whether it's clock-wise or counter clock-wise it will end in the opposite place.