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In-s [12.5K]
3 years ago
9

Can you help me solve this problem

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
6 0
Subtract 0.1125 and 0.75 and if your answer is 15% of 0.1125 then she did cut the amount of fabric off corectly
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Firlakuza [10]

Answer:

The graph increases

Step-by-step explanation:

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3 years ago
You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp
Katena32 [7]
Let's move like a crab, backwards some.

after 2 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &2&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2

after 3 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{original amount deposited}\to &\$1000\\&#10;r=rate\to 3\%\to \frac{3}{100}\to &0.03\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &3&#10;\end{cases}&#10;\\\\\\&#10;A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3

is that enough to pay the $1100?


now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000   <---- standard form.
8 0
3 years ago
30 POINTS,NEED HELP ASAP !!!
zaharov [31]

Answer: OPTION A.

Step-by-step explanation:

You can observe that in the figure CDEF the vertices are:

C(-2,-1),\ D(-2,0),\ E(2,2)\ and\ F(2,1)

And in the figure C'D'E'F'  the vertices are:

C'(-8,-4),\ D'(-8,0),\ E'(8,8)\ and\ F'(8,4)

For this case, you can divide any coordinate of any vertex of the figure C'D'E'F' by any coordinate of any vertex of the figure CDEF:

For C'(-8,-4) and C(-2,-1):

\frac{-8}{-2}=4\\\\\frac{-4}{-1}=4

Let's choose another vertex. For E'(8,8) and E(2,2):

\frac{8}{2}=4\\\\\frac{8}{2}=4

You can observe that the coordinates of C' are obtained by multiplying each coordinate of C by 4 and the the coordinates of E' are also obtained by multiplying each coordinate of E by 4.

Therefore, the rule that yields the dilation of the figure CDEF centered at the origin is:

(x, y)→(4x, 4y)

7 0
3 years ago
Read 2 more answers
Patricia knows she can request a free copy of her credit report each year, but now that she's got the document, she's not sure w
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Step-by-step explanation:

3 0
3 years ago
2w^2-11w=-12 <br> a w=3/2 or 4<br> b w=1 or 12<br> c w=1 or 7<br> d w = 2.5 or 6
dlinn [17]
Hey mate !!
Here's your answer !!


2w^2 - 11w = -12
2w^2 -11w + 12 = 0
2w^2 - 8w - 3w + 12 = 0

2w ( w - 4) -3 ( w - 4) = 0
(2w - 3) ( w - 4) = 0

Hence

2w - 3 = 0
2w = 3
w = 3/2

w - 4 = 0
w = 4

Hence value of w are 4 and 3/2

Hope this helps!!
Cheers!!
7 0
3 years ago
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