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3 years ago

What are the first four terms of the sequence an=n2+4

Mathematics

1 answer:

Igoryamba3 years ago

7 0

Step-by-step explanation:

Given formula

an = n² + 4

Now the first four terms of the sequence are

a1 = 1² + 4 = 5

a2 = 2² + 4 = 4 + 4 = 8

a3 = 3² + 4 = 9 + 4 = 13

a4 = 4² + 4 = 16 + 4 = 20

The terms are

5 , 8 , 13 and 20.

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Are the expressions bh/2 and (1/2)bh equivalent expressions?

andreev551 [17]

Bh/2 = (1/2)bh, so <span>bh/2 and (1/2)bh equivalent expressions</span>

4 0

3 years ago

The point P= (x,-1/7) lies on the unit circle shown below. What is the value of x in simplest form?

ipn [44]

Answer:

$x^2 + \frac{1}{49} =1$

And solving for x we got:

$x^2 = 1- \frac{1}{49}$

$x^2 = \frac{48}{49}$

And taking square root we got:

$x = \sqrt{\frac{48}{49}}= \frac{\sqrt{48}}{7} = \frac{4\sqrt{3}}{7}$

Step-by-step explanation:

For this case we have the following point given $P(x , -1/7)$

And we want to find the value of x, since P lies on the unitray circle if we find the distance from P to the center of the unitary circle (0,0) we need to get 1. Using the definition of Euclidean distance that means:

$d = \sqrt{(x -0)^2 +(-1/7 -0)^2}=1$

And if we square both sides of the last equation we got:

$x^2 + \frac{1}{49} =1$

And solving for x we got:

$x^2 = 1- \frac{1}{49}$

$x^2 = \frac{48}{49}$

And taking square root we got:

$x = \sqrt{\frac{48}{49}}= \frac{\sqrt{48}}{7} = \frac{4\sqrt{3}}{7}$

3 0

3 years ago

A recipe for granola bars calls for 2/3 cup of oats. How much of the pats would you use to make 1/2 of the amount in the origina

Veseljchak [2.6K]

Answer:

1/3 cups

Step-by-step explanation:

If you want to make half of the recipe that requires 2/3 cup oats, then you would use half the oats. Half of 2/3 cup of oats is 1/3 cup of oats.

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3 years ago

Please answer correctly !!!!!! Will mark brainliest !!!!!!!!!

Harlamova29_29 [7]

Answer:

-2 = not in domain

0= in domain

3= in domain

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3 years ago

What is the first step in simplifying

seraphim [82]

Distribute the negative b and negative one to he terms in the parentheses
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3 years ago