In this case it is to find the roots of the polynomial.
We have then:
2x ^ 2-5x + 1 = 3
Rewriting:
2x ^ 2-5x-2 = 0
Applying resolver we have
x = (- b +/- root (b ^ 2 - 4ac)) / (2a)
Substituting values:
x = (- (- 5) +/- root ((- 5) ^ 2 - 4 (2) (- 2))) / (2 (2))
x = (- (- 5) +/- root ((25 + 16)) / (2 (2))
x = (5 +/- root (41))) / (4)
x = ((5/4) +/- (root (41)) / 4)
Answer:
x = ((5/4) +/- (root (41)) / 4)
(option 4)
Answer:
I believe you are correct
Hope This Helps! Have A Nice Day!!
Answer:
Step-by-step explanation:
Given expression:
Remove parentheses:
Collect like terms:
Combine like terms:
3y^-4/3 x 2 3/y
Write in exponential form with the base of y
= 3y^-4/3 x 2y^1/3
Calculate the product
= 6y^-1
Any expression raised to the power of equals its reciprocal
= 6 x 1/y
Calculate the product
= 6/y
Answer:
It's D. 53.1°
Step-by-step explanation:
