Answer:
Explanation:
Initial momentum is 1.5e6(3) = 4.5e6 kg•m/s
An impulse results in a change of momentum
The tug applied impulse is 12000(10) = 120000 N•s or 0.12e6 kg•m/s
The remaining momentum is 4.5e6 - 0.12e6 = 4.38e6 kg•m/s
The barge velocity is now 4.38e6 / 1.5e6 = 2.92 m/s
The tug applies 0.012e6 N•s of impulse each second.
The initial barge momentum will be zero in
t = 4.5e6 / 0.012e6 = 375 s or 6 minutes and 15 seconds
To stop the barge in one minute(60 s), the tug would have to apply
4.5e6 / 60 = 75000 N•s /s or 75 000 N
Answer:
B) 10 microJoule
Explanation:
Given
v = 100 micrometer/s
F = 0.1 N
t = 1 s
we get the displacement as follows
d = v*t ⇒ d = (100 micrometer/s)*(1 s) = 100 micrometer
then we apply the formula
W = F*d*Cos ∅
⇒ W = (0.1 N)*(100 micrometer)*Cos 0°
⇒ W = 10 microJoule
static electricity and friction
<h2>
Answer:</h2>
<em><u>Angle = 9.965° South of West.</u></em>
<h2>
Explanation:</h2>
In the question,
The speed of the Plane w.r.t to Wind = 256 m/s
Speed of the Wind w.r.t to Ground = 44.3 m/s
Direction of Wind = North from South
Direction Plane wishes to go = West
So,
Using the vectors,
<u>Speed of Wind w.r.t Ground</u> is given by,
<u>Resultant speed of Plane w.r.t Ground</u> is given by,
So,
From the <u>Vector's Triangle Sum property,</u>
<em><u>Therefore, the plane has to move in the direction of 'III quadrant' or 'South-West' direction.</u></em>
Now,
In the triangle, using <u>Pythagoras Theorem</u>,
The speed of the plane = 252.13 m/s
Now,
<u>Therefore, the angle at which the plane should fly to go West is</u><em><u> = 9.965° South of West.</u></em>
The gravitational force of the planet pulling on the sun is equal to the gravitational force of the sun pulling on the planet
Explanation:
We can solve this problem by applying Newton's third law, which states that:
<em>"When an object A exerts a force (called </em><em>action</em><em>) on an object B, then object B exerts an equal and opposite force (called </em><em>reaction</em><em>) on object A"</em>
In this problem, we can identify:
- The sun as object A
- The planet as object B
By applying Newton's third law, we can state that:
- The action is the gravitational force exerted by the sun on the planet
- The reaction is the gravitational force exerted by the planet on the sun
According to the law, the two forces are equal in magnitude and opposite in direction: so, we can conclude that
The gravitational force of the planet pulling on the sun is equal to the gravitational force of the sun pulling on the planet
Learn more about Newton's third law:
brainly.com/question/11411375
#LearnwithBrainly