Walking across a carpet is an example of charge being transferred by
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Case d) has the strongest gravitational force
Explanation:
The magnitude of the gravitational force between two objects is given by the equation:
where :
is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
a) For this pair of objects:
m1 = 10 kg
m2 = 2 kg
r = 30 km = 30,000 m
So the gravitational force is
b) For this pair of objects:
m1 = 10 kg
m2 = 10 kg
r = 30 km = 30,000 m
So the gravitational force is
c) For this pair of objects:
m1 = 2 kg
m2 = 2 kg
r = 10 km = 10,000 m
So the gravitational force is
d) For this pair of objects:
m1 = 10 kg
m2 = 10 kg
r = 10 km = 10,000 m
So the gravitational force is
Therefore, the strongest gravitational force is in case d).
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at the lowest point in the trajector, the kinetic energy of the bob is 300 J.
Explanation:
The total mechanical energy of the bob at any point of its motion is given by
Where
is the kinetic energy, where
m is the mass of the bob
v is its speed
is the gravitational potential energy, where
g is the acceleration of gravity
h is the height of the bob, measured with respect to the lowest point of the trajector
In absence of friction, the total mechanical energy E remains constant. So we have:
- When the bob swings upward, the PE increases (because h increases) and the KE decreases (so the speed decreases). At the highest point in the trajector, the speed of the bob is zero (v=0), so its KE is also zero and all the mechanical energy is potential energy: U = 300 J
- When the bob swings downward, the PE decreases (because h decreases) and the KE increases (so the speed increases). At the lowest point in the trajectory, the height has become zero (h=0), so the PE is zero and all the mechanical energy is kinetic energy: KE = 300 J
Therefore, at the lowest point in the trajector, the kinetic energy of the bob is 300 J.
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