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4 years ago

Walking across a carpet is an example of charge being transferred by

Physics

1 answer:

Sati [7]4 years ago

8 0

static electricity and friction

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Lillle is running. She increases her initial speed of 30 km/h to 40 km/h so she

Alex777 [14]

Answer

$200km {h}^{ - 2}$

Explanation

$Acceleration = \frac{final \: \: \: velocity - initial \: \: velocity }{time} \\ = \frac{(40 - 30)km {h}^{ - 1} }{0.05h} \\ = \frac{10}{0.05} \\ = 200km {h}^{ - 2}$

Hope this helps you.

Let me know if you have any other questions :-):-)

6 0

3 years ago

Read 2 more answers

A person is walking briskly in a straight line. The figure shows a graph of the person’s position x as a function of time t. Wha

Nina [5.8K]

The average velocity over the interval $6\le t\le 10$ is

$\dfrac{x(10)-x(6)}{10\,\mathrm s-6\,\mathrm s}=\dfrac{6\,\mathrm m-2.67\,\mathrm m}{4\,\mathrm s}=0.8325\,\dfrac{\mathrm m}{\mathrm s}$

where $x(t)$ is the person's position at time $t$ . I've taken the liberty of estimating $x(6)\approx2.67\,\mathrm m$ . The closest choice among the answers is $0.8\,\dfrac{\mathrm m}{\mathrm s}$ .

7 0

3 years ago

Which tool would you use to measure the amount of rainfall? a. graduated cylinder b. stopwatch c. scale d. thermometer

Fittoniya [83]

A graduated cylinder measures the volume of a liquid.

A stopwatch measures the amount of time that elapses.

A scale measures the mass of objects.

A thermometer measures the temperature of any object.

Because we are measuring rain, a liquid, we would want to use a tool that would allow us to collect the rain for measuring. Therefore, the tool e would use to measure the amount of rainfall would be A. a graduated cylinder.

5 0

3 years ago

Read 2 more answers

A 50.0-kg girl stands on a 9.0-kg wagon holding two 13.5-kg weights. She throws the weights horizontally off the back of the wag

Kobotan [32]

Do you still need help with this question??

5 0

3 years ago

Can someone please give me the (Answers) to this? ... please ... I need help….

IceJOKER [234]

#1.

Car 1 weighs 300 kilograms and is moving right at 3 meters per second (m/s)

v1 (before) = 3 m/s

v2 (before) = -1 m/s

v1 (after) = 0.5 m/s

#2.

Law of conservation of momentum

momentum before collorion = momentim after collosion

MV + mv = MV' + mv'

1500x25+ 1000x5

37500 + 15000

6 0

2 years ago