Spring C stretches 100 cm.
Explanation:
The spring constant is simply the stiffness of the spring. The higher the spring constant the more stiff the spring is.
Spring constant shows the force needed to stretch a spring from it's equilibrium position. If a material requires more force to cause it to stretch, it will have a high spring constant.
According to hooke's law "the force needed to extended an elastic material is directly proportional to its extension"
F = ke
k is the spring constant
e is the extension
We see that the spring that stretches by 100 is the less stiff compared to other springs. It has the smallest spring constant.
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Julia walks from the park, which is six blocks east of her house, to the store, which is three blocks east of her house. Julia walks for 5 minutes. This walk's average speed will be 1.2 blocks per minute. Option B is correct.
<h3>What is displacement?</h3>
Displacement is defined as the shortest distance between the two points. Distance is the horizontal length covered by the body. While displacement is the shortest distance between the two points.
Displacement is a vector quantity .its unit is m.
The average velocity on this walk will be;
![\rm v_{avg}= \frac{d}{t} \\\\ \rm v_{avg}= \frac{6 \ block+ 3 \ block }{5 \ minute } \\\\ v_{avg}=1.4 \ block /min](https://tex.z-dn.net/?f=%5Crm%20v_%7Bavg%7D%3D%20%5Cfrac%7Bd%7D%7Bt%7D%20%5C%5C%5C%5C%20%5Crm%20v_%7Bavg%7D%3D%20%5Cfrac%7B6%20%5C%20block%2B%203%20%5C%20block%20%7D%7B5%20%5C%20minute%20%7D%20%5C%5C%5C%5C%20v_%7Bavg%7D%3D1.4%20%20%5C%20block%20%2Fmin)
Hence option B is correct.
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Answer:
50 meters
Explanation:
Let's start by converting to m/s. There are 3600 seconds in an hour and 1000 meters in a kilometer, meaning that 72km/h is 20m/s.
![v_f=v_o+at](https://tex.z-dn.net/?f=v_f%3Dv_o%2Bat)
Since the car starts at rest, you can write the following equation:
![20=0+a(5) \\\\a=20\div 5=4 m/s^2](https://tex.z-dn.net/?f=20%3D0%2Ba%285%29%20%5C%5C%5C%5Ca%3D20%5Cdiv%205%3D4%20m%2Fs%5E2)
Now that you have the acceleration, you can do this:
![d=v_o+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=d%3Dv_o%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
Once again, there is no initial velocity:
![d=\dfrac{1}{2}(4)(5)^2=2 \cdot 25=50m](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7B1%7D%7B2%7D%284%29%285%29%5E2%3D2%20%5Ccdot%2025%3D50m)
Hope this helps!
Answer:
option C
Explanation:
given,
Force on the object = 10 N
distance of push = 5 m
Work done = ?
we know,
work done is equal to Force into displacement.
W = F . s
W = 10 x 5
W = 50 J
Work done by the object when 10 N force is applied is equal to 50 J
Hence, the correct answer is option C