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Mamont248 [21]
3 years ago
6

Help me calculate the kinetic energy (just the middle column) ASAP! SHOW WORK! ON PAPER

Physics
1 answer:
lukranit [14]3 years ago
3 0

Answer:

Explanation:

I can tell you what the answers for the middle column are, but if you don't know how to solve total energy problems, they won't make any sense to you at all.

First row, KE = 0

Second row, KE = 220500 J

Third row, KE = 183750 J

Fourth row, KE = 205800 J

That's also not paying any attention to significant digits because your velocity only had 1 and that's not enough to do the problem justice. I left all the digits in the answer. Round how your teacher tells you to.

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In case of frequency of light what changes​
maks197457 [2]

Answer:

frequency remains constant when light passes through different mediums . only speed changes and due to it , wavelength also changes. one way of changing the frequency is by Doppler effect, where the apparent frequency changes due to motion of the source ,observer or both of them.

Explanation:

hope it helps

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Thank u ✌️

6 0
3 years ago
What is the best approximate value for the elastic potential energy (EPE) of the spring elongated by 3.0 meters?
klasskru [66]

P.E=0.0675 J

Explanation:

Elastic potential Energy=Force × distance of displacement

The formula to apply is;

P.E=1/2 ks²

where k is the spring constant given as; 1.5 *10^-2 N/m  and s is the displacement

In this case,

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Elastic potential energy:brainly.com/question/1352053

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3 years ago
A 150 kg line backer sacks the 120 kg quarterback. With what force is the quarterback sacked if the line backer has an accelerat
Gekata [30.6K]

Answer:

The force required to move the quarterback with linebacker is <u>1215 N</u>

Explanation:

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\text { Moved at an acceleration }(a)=4.5 \mathrm{m} / \mathrm{s}^{2}

Using Newton's second law, it is established that  F = Ma

Where F is net force acting on the system, a is the acceleration and M is mass of the two object \left(m_{1}+m_{2}\right)

Now consider both \mathrm{m}_{1} \text { and } \mathrm{m}_{2}as a system, so net force acting on the system is \text { Force }=\left(m_{1}+m_{2}\right) a

Substitute the given values in the above formula,

\text { Force }=(150+120) \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

\text { Force }=270 \mathrm{kg} \times 4.5 \mathrm{m} / \mathrm{s}^{2}

Force = 1215 N

<u>1215 N </u>is the force required to move the quarterback with linebacker.

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