Answer:
R^3 = GM / ω^2
R^3 = (6.67 * 10^-11) * (5.98 * 10^24) / (0.00007272)^2
R^3 = 7.54 * 10^22
R = 42,251,269
R = 4.225 * 10^7 m
4.225 * 10^7
Explanation:
Answer:
2.57 seconds
Explanation:
The motion of the ball on the two axis is;
x(t) = Vo Cos θt
y(t) = h + Vo sin θt - 1/2gt²
Where; h is the initial height from which the ball was thrown.
Vo is the initial speed of the ball, 22 m/s , θ is the angle, 35° and g is the gravitational acceleration, 9.81 m/s²
We want to find the time t at which y(t) = h
Therefore;
y(t) = h + Vo sin θt - 1/2gt²
Whose solutions are, t = 0, at the beginning of the motion, and
t = 2 Vo sinθ/g
= (2 × 22 × sin 35°)/9.81
= 2.57 seconds
Answer:
False
Explanation:
When the location of the poles changes in the z-plane, the natural or resonant frequency (ω₀) changes which in turn changes the damped frequency (ωd) of the system.
As the poles of a 2nd-order discrete-time system moves away from the origin then natural frequency (ω₀) increases, which in turn increases damped oscillation frequency (ωd) of the system.
ωd = ω₀√(1 - ζ)
Where ζ is called damping ratio.
For small value of ζ
ωd ≈ ω₀
When two charged plates are separated by a distance, the potential difference between the plates is 54 Volts.
<h3>What is uniform electric field?</h3>
The electric field intensity which does not increase or decrease with time or remain constant is called the uniform electric field.
Given is the plates separated by distance d = 15 cm =0.15 m, electric field E= 360 N/C.
The relation between the electric field and voltage is
E=V/d
Substitute the values into the expression to get the potential difference V,
V = 360 x 0.15
V = 54 Volts
Thus, the potential difference between the plates is 54 Volts.
Learn more about uniform electric field.
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D. density is your answer because density is an intensive property. By the way is this for FLVS?
