Answer:
Photomath
Step-by-step explanation:
It looks like someone else is answering this for me so I'll just give ya a nudge. In the future as long as you can put it into an equation Photo math helped me a lot in Middle and Highschool.
Answer:
D. 7
Step-by-step explanation:
The question is incomplete. Here is a possible complete question
For the given expression, which whole number (w) will make the expression true? 5/6 < w/6
A. 3
B. 4
C. 5
D. 7
Given the inequality expression:
5/6 < w/6
Cross multiply
5×6 < 6×w
30<6w
Divide both sides by 6
30/6 = 6w/6
5<w
Reciprocate both sides(this will change the sense of the inequality)
1/5>1/w
Cross multiply
w > 5×1
w>5
This shows that the value of w is a value greater than 5 but not 5. According to the option, the only value greater than 5 is 7. Hence the whole number (w) that will make the expression true is 7
Answer:
Step-by-step explanation:
1) A = x
Flower garden is in rectangular shape. In rectangle, opposite sides are equal.
2) The entire garden is in rectangular shape. In rectangle, opposite sides are equal.
B + x+ 4 = 10x + 6
Take x and 4 to other side to find the value of B. When taking to other side of equal to sign, the sign of x and 4 will change
B = 10x + 6 - x - 4
B = 10x - x + 6 - 4 {Combine like terms}
B = 9x + 2
3) C + x -2 = 5x -3
C = 5x - 3 - x +2
C = 5x -x - 3 + 2
C = 4x - 1
4) Area of Vegetable garden = length * width
= (5x - 3) * (9x + 2)
Use FOIL method
= 5x *9x + 5x*2 + (-3)*9x + (-3)*2
= 45x² + 10x - 27x - 6
= 45x² - 17x - 6
Answer:
The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:
The information provided is:
<em>σ</em> = $60
<em>MOE</em> = $2
The critical value of <em>z</em> for 95% confidence level is:
Compute the sample size as follows:
![n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%20%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.96\times 60}{2}]^{2}](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.96%5Ctimes%2060%7D%7B2%7D%5D%5E%7B2%7D)
Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.
