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Lapatulllka [165]
3 years ago
8

How would an increase in carbon dioxide concentration in the atmosphere change the green house effect? A. Carbon dioxide would c

hange the greenhouse gases. B. It would make the greenhouse effect stronger. C. There would be less of a greenhouse effect. D. The greenhouse effect would stop happening.
Chemistry
1 answer:
Elis [28]3 years ago
7 0

Answer:

D

Explanation:

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An ionic bond involves two elements...
valina [46]

Answer:

a metal and a nonmetal element

Explanation:

6 0
3 years ago
What effect would you expect this to have on CO2 levels in the atmosphere?
VLD [36.1K]

expect what to have?!?!?!?

5 0
2 years ago
Compare and contrast the concepts of average mass and relative mass. Which one is more accurate, and why? Why is the one you did
Brut [27]

Answer:

Relative and average atomic mass both describe properties of an element related to its different isotopes.

Explanation:However, relative atomic mass is a standardized number that's assumed to be correct under most circumstances, while average atomic mass is only true for a specific sample.

4 0
3 years ago
Read 2 more answers
Help please !!!!!!!!
Elena L [17]

Answer:

Option B. 2096.1 K

Explanation:

Data obtained from the question include the following:

Enthalpy (H) = +1287 kJmol¯¹ = +1287000 Jmol¯¹

Entropy (S) = +614 JK¯¹mol¯¹

Temperature (T) =.?

Entropy is related to enthalphy and temperature by the following equation:

Change in entropy (ΔS) = change in enthalphy (ΔH) / Temperature (T)

ΔS = ΔH / T

With the above formula, we can obtain the temperature at which the reaction will be feasible as follow:

ΔS = ΔH / T

614 = 1287000/ T

Cross multiply

614 x T = 1287000

Divide both side by 614

T = 1287000/614

T = 2096.1 K

Therefore, the temperature at which the reaction will be feasible is 2096.1 K

5 0
3 years ago
The poisonous gas hydrogen sulfide, H2S, can be neutralized with a base such as sodium hydroxide,
mariarad [96]

Answer:

It's not correct. For balancing, we need to put the coefficients in the molecule, not in the athom. Because if you do this, you're creating another molecule, instead of a balacing, for which the reaction may not happen - but anyway, it would be another reaction.

The correct balacing is:

2NaOH + 1H2S → 1Na2S + 2H2O

Explanation:

Look: Na2OH does not even exist. OH has only one free link, so he can't - in normal conditions - make another one with any athom. That's why we should write 2NaOH instead of Na2OH. The first means "2 mols of NaOH".

4 0
3 years ago
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