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wariber [46]
3 years ago
9

What is the difference between nuclear fusion and nuclear fission?

Chemistry
1 answer:
True [87]3 years ago
4 0

Answer:

[Fusion: Nuclei Fuse together and release energy]  [Fission: Pressure and energy is released. This release of energy, is what causes the unstable atom to split to an isotope. I hope this helps!]

[isotopes can split too. At least some.]

Explanation:

Imagine you are trying to push something heavy, fusion is how you can join together and help each other to push this heavy material.

Fun fact! Heavier materials have more inertia against other forces acting on them.

You push harder, harder and harder! Until its pushed.

This will release a lot of energy which escalates to an extended length.

It might not be the finest example, it helped me to understand the basics.

Fission. Imagine having so much energy, in this case, try thinking of so many people in a tight space. What do you do? You will eventually start to escape and leave the room. This is the act of splitting the atom.

This won't be the same than how it was before.

Again, Energy is released (energy!!).

For anyone struggling with this, although it might not be the best idea, I would recommend researching the more advaced options for this topic.

This will give you a wide range of information which can develop your current knowledge about, "Nuclear Fission and Fusion."

It will be difficult, it definitely was for me when I was a child (starting to study science).    

Just keep trying, you'll get it.

You might be interested in
Convert 5.4g of NaCl to moles
sammy [17]

Answer:

.0924 moles of NaCl

Explanation:

So you know you have 5.4 g of NaCl and you need to know how many moles there are in this amount of NaCl

  1. You'll need to find the atomic mass of the compound NaCl to help you solve for moles
  • Sodium (Na) on the periodic table has a mass of 22.99
  • Chlorine (Cl) on the periodic table has a mass of 35.45

Add these two together----> 22.99 + 35.45 = 58.44

Now you can calculate for moles

<u>Written-out method:</u>

<u>5.4 grams of NaCl  |   1 mole of  NaCl              </u>

                                | 58.44 grams NaCl                = .0924 moles of NaCl

<u>Plug into calculator method:</u>

(5.4 g of NaCl/ 58.44g NaCl= .0925 moles)

7 0
3 years ago
Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

8 0
3 years ago
The molarity of concentrated acetic acid is 17.45 M. When acetic acid is diluted in water it is commonly called vinegar with a m
Sladkaya [172]

M1 = 17.45 M

M2 = 0.83 M

V2 = 250 ml

M1. V1= M2. V2

V1 = (M2. V2)/M1 = (0.83× 250)/ 17.45= 11.89 ml

7 0
2 years ago
2. A sample of iron has the dimensions of 2.0 cm x 3.0 cm x
zepelin [54]
Just do it and believe in you self come on man you got it
8 0
3 years ago
Read 2 more answers
What is the percent composition of a copper chloride compound if a 269 g sample contains 127 g of copper and 142 grams of chlori
Tems11 [23]

Answer:

Explanation:

The whole sample is 269

%copper = 127/269 * 100 = 47.2%

%chlorine = 142/269 * 100 = 52.8%

That's all you are asking. Is there more?

5 0
3 years ago
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