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polet [3.4K]
3 years ago
7

How much heat is absorbed during production of 112g of NO by the combination of nitrogen and oxygen? . N2(g)+O2(g)→2NO(g), ΔH =

+ 43 kcal/mol
Chemistry
2 answers:
Lyrx [107]3 years ago
8 0
It is calculated as follows:

112g of NO ( 1 mo NO/Molar mass of NO ) x 43Kcal/ 1 mol NO

For these type of problems, you want to convert the amount given to moles first since kcal is over moles. 
mina [271]3 years ago
4 0

Answer : The heat absorbed during the reaction is 160.4 kcal

Explanation :

First we have to calculate the number of moles of NO.

\text{Moles of }NO=\frac{\text{Mass of }NO}{\text{Molar mass of }NO}

Molar mass of NO = 30 g/mole

\text{Moles of }NO=\frac{112g}{30g/mole}=3.73mole

Now we have to calculate the heat absorbed during the reaction.

\Delta H=\frac{q}{n}

or,

q=\Delta H\times n

where,

\Delta H = enthalpy change = +43 kcal/mol

q = heat absorb = ?

n = number of moles of NO = 3.73 mol

Now put all the given values in the above formula, we get:

q=(+43 kcal/mol)\times (3.73mol)=+160.4kcal

Therefore, the heat absorbed during the reaction is 160.4 kcal

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What protects the cells of plants
gogolik [260]

Explanation:

Plant cells have several structures not found in other eukaryotes. In particular, organelles called chloroplasts allow plants to capture the energy of the Sun in energy-rich molecules; cell walls allow plants to have rigid structures as varied as wood trunks and supple leaves; and vacuoles allow plant cells to change size.

6 0
2 years ago
Read 2 more answers
A 0.133 pg sample of iron-59 produces 242 β-particles per second. what is the half-life of this isotope (in hours)
34kurt
1070 hours.  
1 mole of iron-59 would mass 59 grams, so 0.133 picograms would be 0.133x10^-12 / 59 = 2.25x10^-15 moles of iron-59. Multiplying by Avogadro's number, we can determine the number of atoms of iron-59 we have, so: 2.25x10^-15 * 6.02214x10^23 = 1.35x10^9 
 Since we have 242 decays over a period of 1 second, we can divide the
number of atoms left by the original number of atoms
 (1350000000 - 242)/1350000000
 = 1349999758/1350000000
 = 0.999999820740741 
 And calculate the logarithm to base 2 of that quotient.
 ln(0.999999820740741)/ln(2)
 = -1.79259275281191x10^-7/0.693147180559945
 = -2.58616467481524x10^-7 
 The reciprocal of this number will be the half life in seconds. So
 -1/2.58616467481524x10^-7
 = -3866729.79388461 
 And dividing by 3600 (number of seconds in an hour) will give the half-life in
hours.
 -3866729.79388461 / 3600 = -1074.091609 
 So the half life in hours to 3 significant figures is 1070 hours.
 Dividing that figure by 24 gives a half life of 44.58 days which is in pretty close agreement to the official half-life of 44.495 days for iron-59.

4 0
3 years ago
Pls help asap pls !!
klio [65]

Answer:

basic solution.

Explanation:

has a pH of 12.

it turns clear indicator pink.

it contains hydroxide ions which conduct electricity

3 0
3 years ago
How many grams of oxygen can be obtained from 250. grams of KCIO3?
guapka [62]

Answer:

Keep it simple. If all the oxygen contained in the 200 grams of potassium chlorate is produced in the decomposition, then all we have to do is find out how many grams of oxygen are there in the 200 grams. This we can do by calculating the ratio of oxygen mass to the whole. Using 39.1 for potassium, 35.45 for chlorine and 3 times 16, or 48 for the oxygen, we get a total of 122.55 grams per mole for potassium chlorate, of which 48 grams are oxygen. This ratio is 48/122.55. This ratio times the original 200 grams of the compound, gives us 78.34 grams of oxygen produced.

Explanation:

3 0
2 years ago
PLEASE PEOPLE I NEED HELP PLEASE IF YOU SEE THIS HELP ME ! :,( !!!!! PLEASEEEEEEEEE
Tems11 [23]

Answer:

year 1 is 5.5%

year 2 is 7.5%

year 3 is 10.2%

Explanation:

since,

length of the transect covered in seaweed / total lenth of transect x 100

then,

0.55 / 10.0 x 100 = 5.5

and

0.75 / 10.0 x 100 = 7.5

and

1.02 / 10.0 x 100 = 10.2

you could also just move the decimal to the right once

:)

4 0
3 years ago
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