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Valentin [98]
3 years ago
15

Pls answer with all working out pls

Mathematics
1 answer:
Illusion [34]3 years ago
4 0
If n=5, then substitute the value in every equation, 

a) 6 - 5 = 1
b) 17 - 3(5) = 17 - 15 = 2
c) 3(5) - 4 = 15 - 4 = 11
d) 6(5) - 14 = 30-14 = 16

Hope this helps!
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Factor over the complex numbers: 36x2 + 9.
ludmilkaskok [199]

36x^2+9=(6x)^2-(-9)=(6x)^2-(-3^2)\\\\=(6x)^2-(3i)^2=(6x-3i)(6x+3i)\\\\\text{Used:}\\a^2-b^2=(a-b)(a+b)\\\\i^2=-1

4 0
3 years ago
What are the solutions to the equation?<br> 7x^3=28x
11Alexandr11 [23.1K]

7x³ = 28x is our equation. We want its solutions.

When you have x and different powers, set the whole thing equal to zero.

7x³ = 28x

7x³ - 28x = 0

Now notice there's a common x in both terms. Let's factor it out.

x (7x² - 28) = 0

As 7 is a factor of 7 and 28, it too can be factored out.

x (7) (x² - 4) = 0

We can further factor x² - 4. We want a pair of numbers that multiply to 4 and whose sum is zero. The pairs are 1 and 4, 2 and 2. If we add 2 and -2 we get zero.

x (7) (x - 2) (x + 2) = 0

Now we use the Zero Product Property - if some product multiplies to zero, so do its pieces.

x = 0        -----> so x = 0

7 = 0       -----> no solution

x - 2 = 0   ----> so x = 2   after adding 2 to both sides

x + 2 = 0  ---> so = x - 2  after subtracting 2 to both sides


Thus the solutions are x = 0, x = 2, x = -2.

6 0
3 years ago
Mario deposits $300 in a savings account over the course of a year. He deposits money into the account throughout t next year un
Rainbow [258]

 The answer is an=2⋅ 300^n−1.

7 0
3 years ago
What are the coordinates of the centroid of a triangle with vertices A(−3, 1) , B(1, 6) , and C(5, 2) ? Enter your answer in the
kirza4 [7]

<u>ANSWER</u>: The centroid is (1,3)


<u>Explanation:</u>

The centroid is the intersection of the medians of the triangle.

So we need to find the equation of any two of the medians and solve simultaneously.


Since the median is the straight line from one vertex to the midpoint of the opposite side, we find the midpoint of any two sides.


We find the midpoint of AC using the formula;

N=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})



N=(\frac{-3+5}{2}, \frac{1+2}{2})


N=(\frac{2}{2}, \frac{3}{2})


N=(1, \frac{3}{2})


The equation of the median passes through B(1,6) and N=(1, \frac{3}{2}).


This line is parallel to the y-axis hence has equation

x=1-------first median.



We also find the midpoint M of BC.

M=(\frac{1+5}{2}, \frac{6+2}{2})


M=(\frac{6}{2}, \frac{8}{2})


M=(3, 4)


The slope of the median, AM is


Slope_{AM}=\frac{4-1}{3--3}


Slope_{AM}=\frac{3}{6}


Slope_{AM}=\frac{1}{2}


The equation of the median AM is given by;


y-y_1=m(x-x_1)


We use the point M and the slope of AM.


y-4=\frac{1}{2}(x-3)


2y-8=(x-3)


2y-x=-3+8


2y-x=5-------Second median

We now solve the equation of the two medians simultaneously by putting x=1 in to the equation of the second median.


2y-1=5


2y=5+1


2y=6


y=3


Hence the centroid has coordinates (1,3)























7 0
3 years ago
Read 2 more answers
Express this to the nearest whole .
RSB [31]

Answer:

its 30 the a in thst problem is silents

Step-by-step explanation:

3 0
3 years ago
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