Answer:
12s - 16t
Step-by-step explanation:
2(3s + t) + 2(3s - 9t)
6s + 2t + 6s - 18t
12s + 2t - 18t
12s - 16t
Your answer is 25. You do 40 times 5 divided by 8 or 8 times 5 is 40 and 5 times 5 is 25. Hope this helps
Answer:

Where x represent the distance and t the time if we replace the info given we got:

Then the average speed for this case in m/s is 3.704 for the 200 meter race
Step-by-step explanation:
The problem provides for this case the amount of distance travelled by Jessica in a given time. And we know that travels 200m in 54 seconds.
We want to find the average speed and we can use the following formula:

Where x represent the distance and t the time if we replace the info given we got:

Then the average speed for this case in m/s is 3.704 for the 200 meter race
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
Learn more about probability at brainly.com/question/24756209
#SPJ4
Answer:
(a) The complete frequency distribution is shown below.
(b)The histogram is attached below.
Step-by-step explanation:
The data for the number of miles biked by eighteen cyclists last week is as follows:
7, 21, 12, 4, 5 , 18, 10, 23, 11, 13, 20, 4, 24, 4, 9, 11, 6, 23
(a)
A frequency distribution is to formed for the data with a class width of 6.
The class intervals are provided.
The complete frequency distribution is as follows:
Class Interval Frequency
2 to 7 6
8 to 13 6
14 to 19 1
20 to 25 5
(b)
The histogram is attached below.