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salantis [7]
3 years ago
9

HELP ASAP WILL MARK BRAINLIST ALOT OF POINTS

Mathematics
1 answer:
AnnZ [28]3 years ago
4 0

Answer:

Step-by-step explanation:

We do not add the triangles in because they are the bases and the bases do not get added in the lateral surface areas.

From left to right

Rectangle 1

A = lw = 9.9 *20 =198

Rectangle 2

A = lw = 6.8 *20 =136

Rectangle 3

A = lw = 9.9 *20 =198

Add them together

198+136+198

532

LSA = 532 yds ^2

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The width of a rectangle measures (3s+t) centimeters,and it’s length measures (3s-9t) centimeters. Which expression represents t
andreyandreev [35.5K]

Answer:

12s - 16t

Step-by-step explanation:

2(3s + t) + 2(3s - 9t)

6s + 2t + 6s - 18t

12s + 2t - 18t

12s - 16t

3 0
3 years ago
What is the solution to the proportion? 5/8 = m/40
Triss [41]
Your answer is 25. You do 40 times 5 divided by 8 or 8 times 5 is 40 and 5 times 5 is 25. Hope this helps
4 0
3 years ago
Read 2 more answers
Jessica ran on the track team at her school. She finished the 200-meter race in 54 seconds. What was jessica's average speed,in
Scrat [10]

Answer:

v =\frac{x}{t}

Where x represent the distance and t the time if we replace the info given we got:

v = \frac{200m}{54 s} =3.704 \frac{m}{s}

Then the average speed for this case in m/s is 3.704 for the 200 meter race

Step-by-step explanation:

The problem provides for this case the amount of distance travelled by Jessica in a given time. And we know that travels 200m in 54 seconds.

We want to find the average speed and we can use the following formula:

v =\frac{x}{t}

Where x represent the distance and t the time if we replace the info given we got:

v = \frac{200m}{54 s} =3.704 \frac{m}{s}

Then the average speed for this case in m/s is 3.704 for the 200 meter race

4 0
4 years ago
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then what is the pr
andreyandreev [35.5K]

If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500

Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.

We have to find the probability of observing at least one car during any 5 minute time interval.

Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.

Probability during 20 minutes interval=609/625

Probability during 1 minute interval=609/625*20

=609/12500

Probability during 5 minute interval=(609/12500)*5

=609/2500

Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.

Learn more about probability at brainly.com/question/24756209

#SPJ4

8 0
2 years ago
Please help will mark brainliest
beks73 [17]

Answer:

(a) The complete frequency distribution is shown below.

(b)The histogram is attached below.

Step-by-step explanation:

The data for the number of miles biked by eighteen cyclists last week is as follows:

7, 21, 12, 4, 5 , 18, 10, 23, 11, 13, 20, 4, 24, 4, 9, 11, 6, 23

(a)

A frequency distribution is to formed for the data with a class width of 6.

The class intervals are provided.

The complete frequency distribution is as follows:

Class Interval      Frequency

     2 to 7                    6

    8 to 13                    6

   14 to 19                    1

  20 to 25                  5

(b)

The histogram is attached below.

7 0
3 years ago
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