Question

A car rental agency has 9 midsized and 16 compact cars on its​ lot, from which 6 will be selected. Assuming that each car is equally likely to be selected and the cars are selected at​ random, determine the probability that the cars selected consist of 3 midsized cars and 3 compact cars. What is the probability that the cars selected consist of 3 midsized cars and 3 compact​ cars?

Answer 1

Answer:

$9C6 / 25C6$ = 84/177100

Step-by-step explanation:

Here 9 mid sized

16 compact cars

selected = 6

$9C6 / 25C6$ = 84/177100

for  3 mid sized

3 compact cars

then

3Cx/9Cx

divide by 3 we get

Cx/3Cxtaking Cx coomon

it become Cx =1/3 hence the probability is 1/3