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AfilCa [17]
3 years ago
15

Kelly went on vacation to the Hamptons. She was curious about whether rich people own a lot of TVs, so she went door to door in

333 neighborhoods, asking people how many TVs they owned. Here's what she found:
The inventor of the flat-screen TV lived in neighborhood AAA. He owned 787878 TVs.
Every home in neighborhood BBB owned 333 TVs.
TV ownership in neighborhood CCC was normally distributed with a median of 666 TVs.
In neighborhood AAA, the median number of TVs will likely be

the mean.
In neighborhood BBB, the median number of TVs will be

the mean.
In neighborhood CCC, the median number of TVs will likely be

the mean.
Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

In neighborhood AAA, the median number of TVs will likely be < the mean.

In neighborhood BBB, the median number of TVs will be ==equals the mean.

In neighborhood CCC, the median number of TVs will likely be ==equals the mean.

Step-by-step explanation:

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What is P(4 ≤ X ≤ 6)? Explain. <br> If P(X ≤ a) = 0.2, what is a? Explain.
melamori03 [73]

Answer:

(a) 0.4

(b) a = 3

Step-by-step explanation:

(a) The area under the curve from x=4 to x=6 is 0.2 units high and 2 units wide, so is 0.2·2 = 0.4. (The area of a rectangle is the product of length and width.)

(b) The area is 0.2 and the height of the curve is 0.2, so the width of the region of concern is 0.2/0.2 = 1. (Again, area = height·width, or width = area/height.) 1 unit from the left end is found at X=3, so a = 3.

4 0
2 years ago
Verify the identity 6cos^2(x) -3 = 3 - 6sin^2(x)
Lorico [155]

Answer:

It is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x .

Step-by-step explanation:

We already have the identity of x as \sin ^{2}x + \cos ^{2}x = 1 .......... (1)  .

So, from equation (1) we can write that

\cos ^{2} x = 1 - \sin ^{2} x

⇒ 6\cos ^{2} x = 6 - 6 \sin ^{2} x

⇒ 6\cos ^{2} x -3 = 6 - 6 \sin ^{2}x -3

⇒ 6\cos ^{2}x -3 = 3 - 6\sin ^{2} x

Hence, it is proved that  6\cos ^{2}x -3 = 3 - 6\sin ^{2} x . (Answer)

5 0
3 years ago
how far would a 4.0 cm tall object be located from a reflecting surface with a focal lenght that is equal to 5 cm if it is to cr
katrin [286]

Answer:

HERE IS YOUR ANSWER

Step-by-step explanation:

Use the mirror equation:

1/di + 1/do = 1/f

where di = -10 cm and f = +15 cm. (Note that di is negative if the image is virtual.)

Substitute and solve for do.

1/do + 1/(-10 cm) = 1/(15 cm)

1/do = 1/(15 cm) - 1/(-10 cm) = 5/(30 cm)

do = 6 cm

Hope it helps you

Regards,

Rachana

5 0
3 years ago
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nasty-shy [4]

Answer:

D 90

Step-by-step explanation:

x/4 ≥ 20

Multiply each side by 4

4*x/4 ≥ 20*4

x ≥ 80

The only number greater than or equal to 80 is 90

7 0
3 years ago
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