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sveta [45]
3 years ago
7

If the length of the legs of a right triangle are 5 m and 7 m, what is the length of the hypotenuse?

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

c = 8.60232526704263

c \approx8.6

Step-by-step explanation:

{c}^{2}  =  {a}^{2}  +  {b}^{2}

c =  \sqrt{ {a}^{2}  +  {b}^{2} }

c =  \sqrt{ {5}^{2}  +  {7}^{2} }

c =  \sqrt{25 + 49}

c =  \sqrt{74}

c = 8.60232526704263

c \approx8.6

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the area of a triangle is 384 square feet. If its base is 8 feet longer than its altitude, find the length of the base and the a
REY [17]
A=1/2bh
b=8+h
A=384

384=1/2(bh)
times 2
768=bh
sub
768=b(8+b)
768=8b+b^2
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factor
0=(b-24)(b+32)
set to zero
b-24=0
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false, legnths cannot be negative

b=24
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base=24ft
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6 0
4 years ago
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bagirrra123 [75]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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bonufazy [111]

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