Answer: 5
Step-by-step explanation:
2x=5 so 5÷2 = x (2.5)
3y = 4 so 4÷3 = y (1.3 recurring)
4z = 3 so 3÷4 = z (0.75)
implement: 24x2.5x1.3•x0.75
hope i answered right
Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Answer:
width =19 inches
length= 27 inches
Step-by-step explanation:
Let width be w inches so according to given scenario as length is 8 more than width so the equation becomes
l=8+w inches (Equation 1)
Area of Rectangle= L*w
Area= 513
L*w=513 (Equation 2)
Putting l's value from equation 1 in equation 2
(8+w)w=513
w^2+8w-513=0
Making Factors
w^2+27w-19w-513=0
w(w+27)-19(w+27)=0
(w-19)(w+27)=0
w=19, w=-27
as width cannot be negative so if we only consider w=19 then
l=8+19
l=27
The answer is 26, 27, and 28