Step-by-step explanation:
Please help this is due tomorrow :,)
1 answer:
Given
in ∆ABC
AB = 5cm
BC = 6 cm
AC = 7 cm
now,
as we have to make ∆PQR inside it
than, possibly ∆PQR's sides length is,
PQ = ½ of CB (according to mid point theorem)
→ CB = 6cm → 6/2 → 3cm
PQ = 3cm
QR = ½ of AC
→ AC/2 = 7/2 = 3.5 cm
RP = ½ of AB
→ AB/2 = 5/2 = 2.5cm
therefore, length of
PQ = 3cm
QR = 3.5 cm
PR = 2.5 cm
Hope this answer helps you dear!
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Answer:
The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum level for which the battery pack will be classified as highly sought-after class
At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.
The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours