Answer:
We conclude that commute time in her city is less than the amount reported by the survey which is 25.4 minutes.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 25.4 minutes
Sample mean, 
= 22.1 minutes
Sample size, n = 15
Alpha, α = 0.10
Sample standard deviation, s = 5.3 minutes
First, we design the null and the alternate hypothesis
We use one-tailed t(left) test to perform this hypothesis.
Formula:
Putting all the values, we have
Now, 
Since,
We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
Thus, there is enough evidence to conclude that commute time in her city is less than the amount reported by the survey which is 25.4 minutes.
Formula of direct variation is: y = kx
k is the constant of variation
y is the total value that is directly varies with the changes in x.
in this case. x is represented by a. y is represented by b.
A.) b = 0.7a ⇒DIRECT VARIATION with 0.7 as the constant of variation
B.) b = 1/8 a⁻³ ⇒ Not a direct variation. Because a has a negative exponent
C.) 5(1/a) = b ⇒ Not a direct variation
D.) 1a = b ⇒ DIRECT VARIATION with 1 as the constant of variation
Let the number of runs made on the home run be x, then for the <span>two 3-run home runs, we have 2x
Let the number of runs made in each hit be y, then for the 4 hits that each scored 2 runs, we have 4y.
Thus the algebraic expression to model the total score is 2x + 4y.
Because, there are 3 runs per home run, then x = 3 and because there are 2 runs per hit, then y = 2.
Therefore, the total score is given by 2(3) + 4(2) = 6 + 8 = 14.
</span>
Answer:
a₁₅ = 30
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₅ = 10 and a₁₀ = 20 , then
a₁ + 4d = 10 → (1)
a₁ + 9d = 20 → (2)
Subtract (1) from (2) term by term to eliminate a₁
5d = 10 ( divide both sides by 5 )
d = 2
Substitute d = 2 into (1) and solve for a₁
a₁ + 4(2) = 10
a₁ + 8 = 10 ( subtract 8 from both sides )
a₁ = 2
Then
a₁₅ = 2 + (14 × 2) = 2 + 28 = 30
Growth is shown when a number is increased within a rule. For example: x^2+5, 5 is how much it grows.
