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Bogdan [553]
3 years ago
14

Clara has some sweets. if she packs them in groups of 5, she will have 3 extra sweets. if she packs them in groups of 8, she wil

l have 7 extra sweets. what is the minimum number of sweets clara has?
Mathematics
1 answer:
cricket20 [7]3 years ago
8 0
23 sweets  <====

in groups of 5......4 groups, 3 remaining
in groups of 8.....2 groups, 7 remaining
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Solve for x. x^2−3x−70=0<br><br> x^2 is x to the second power
timurjin [86]
X² <span>− 3x − 70=0
</span>x² + 7x - 10x − 70=0
x(x+7) - 10(x+7) = 0
(x+7)(x-10) = 0

x + 7 = 0   or   x - 10 = 0
x = -7              x = 10

Answer: x=-7,  x=10 
3 0
4 years ago
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A contractor is building a pool labeled ABCD on the plans. If AC = 5y + 6 and BD = 8y-3, what value of y ensures the pool is a r
KIM [24]

The value of y that ensures the pool is a rectangle is 3. Option D

<h3>How to determine the value</h3>

The formula for perimeter of a rectangle is expressed as;

Perimeter = 2 ( length + width)

It is important to note that parallel sides of a rectangle are congruent, that is, they are equal.

Given the sides as;

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  • BD = 8y-3

5y + 6 = 8y -3

collect like terms

5y - 8y = -3 - 6

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Make 'y' the subject

y = 3

Thus, the value of y that ensures the pool is a rectangle is 3. Option D

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3 0
2 years ago
Which of the following is equal to the rational expression when x does not equal 3 or 1 x^2-9/(x-1)(x-3)
yuradex [85]

Answer:

b.  \frac{x+3}{x-1}

Step-by-step explanation:

Given expression is:

\frac{x^{2}-9 }{(x-1)(x-3)}

Let us factorize the numerator using the formula:

a^{2} -b^{2} =(a+b)(a-b)

\frac{(x+3)(x-3)}{(x-1)(x-3)}

Since x ≠ 3, let us cancel the common factor x - 3 in the numerator and in the denominator.

So, \frac{x^{2}-9 }{(x-1)(x-3)} =\frac{x+3}{x-1}

7 0
4 years ago
Wich one is the solution???: 4(2x-1)=-3x+32<br><br><br>i dont understand this thing....
sweet-ann [11.9K]
First let’s multiply. 8x-4=-3x+32. Start collecting like terms on different sides. 8x+3x=32+4. 11x=36. x=36/11. x=3.27.
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3 years ago
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