Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
At the end of the day 797 lockers were closed.
Step-by-step explanation:
So first of all you need to find out how many even numbers there are from 1-900 (which is 450) so you know that 450 are open. In the 3 multiplication tables every second number is even so you know that half of the 450 lockers that was opened was closed again: this meant that 225 lockers remained open.
You also know that every number in the 4 multiplication tables is the second number in the 2 multiplication tables so half of them are closed but you also know that the 900th locker was opened so now you have 113.
So to conclude you do 900-113 which gives you 797 (this is because 113 is the amount of lockers that is open)
Answer: The line starts at 1 positive, then from there go -4 (so go to the left) then 1 down from that point.
Step-by-step explanation: the problem is supposed to have been Y= -4/1 +1
Answer:

Step-by-step explanation:
<u>Given that:</u>
ΔUVW,
Side w = 44 cm, (It is the side opposite to
)
Side u = 83 cm (It is the side opposite to
)
and ∠V=141°
Please refer to the attached image with labeling of the triangle with the dimensions given.
Area of a triangle with two sides given and angle between the two sides can be formulated as:

Where a and b are the two sides and
is the angle between the sides a and b
Here we have a = w = 44cm
b = u = 44cm
and ∠C= ∠V=141
Putting the values to find the area:

So, the <em>area </em>of given triangle to the nearest square centimetre is:

Answer:
WV should be equal to XY
Step-by-step explanation:
since it is the HL postulate meaning hypotenuse and leg, we need to show that the hypotenuses of both triangles are equal since we are already given that one of their legs are congruent. we are also given that they are right triangles.