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Ronch [10]
4 years ago
13

What is a constant in algebra?

Mathematics
2 answers:
nikdorinn [45]4 years ago
5 0

Answer:

A number in an equation that is by itself

Step-by-step explanation:

monitta4 years ago
4 0

Answer:

A constant is a rate of change, or something that can be predicted. For example; numbers of days in a week are constant, aging is constant, the hours in a day are constant, and the time it takes for the light to turn on is constant.

The constant is usually represented at the end of an equation. For example; 2x + 4; 4 is the constant. In (2x^2 + 7x - 9), -9 is the constant.

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Could someone please solve this and explain how to do it?
galben [10]

Answer:

no clue buddy sry

Step-by-step explanation:

4 0
3 years ago
Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4
arsen [322]

we are given

R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k

now, we can find x , y and z components

x=cos(8t),y=sin(8t),z=8ln(cos(t))

Arc length calculation:

we can use formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

x'=-8sin(8t),y=8cos(8t),z=-8tan(t)

now, we can plug these values

L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt

now, we can simplify it

L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8sec(t) dt

now, we can solve integral

\int \:8\sec \left(t\right)dt

=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|

now, we can plug bounds

and we get

=8\ln \left(\sqrt{2}+1\right)-0

so,

L=8\ln \left(1+\sqrt{2}\right)..............Answer

5 0
3 years ago
Today only, a sofa is being sold at a 34% discount. The sale price is $231. What was the price yesterday?
WITCHER [35]

Answer:

$309

Step-by-step explanation:

4 0
3 years ago
If orange juice costs $2.50 for 64 ounces how much will you pay for 6 ounces?
Travka [436]

Answer:

.24 for 6 ounces

Step-by-step explanation:

2.50/64=0.0390625 round up to .04

.04 * 6 = .24

3 0
3 years ago
Landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands
kati45 [8]
This describes a parabolic path that starts at x=0 on a value of y = -5.1.  That's when the rock is below ground in the hole.  To find the answer we need to know the second x axis crossing.  The first is when it is rising and reaches ground level, the second is after it peaks and falls back to the ground and lands. Using the quadratic formula I get the two zeros of this function to be about
x= 15.29, and 66.71.  The rock then lands 66.71 feet from him horizontally.
6 0
3 years ago
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