Answer:

Step-by-step explanation:
This is a conditional probability exercise.
Let's name the events :
I : ''A person is infected''
NI : ''A person is not infected''
PT : ''The test is positive''
NT : ''The test is negative''
The conditional probability equation is :
Given two events A and B :
P(A/B) = P(A ∩ B) / P(B)

P(A/B) is the probability of the event A given that the event B happened
P(A ∩ B) is the probability of the event (A ∩ B)
(A ∩ B) is the event where A and B happened at the same time
In the exercise :



We are looking for P(I/PT) :
P(I/PT)=P(I∩ PT)/ P(PT)

P(PT/I)=P(PT∩ I)/P(I)
0.904=P(PT∩ I)/0.025
P(PT∩ I)=0.904 x 0.025
P(PT∩ I) = 0.0226
P(PT/NI)=0.041
P(PT/NI)=P(PT∩ NI)/P(NI)
0.041=P(PT∩ NI)/0.975
P(PT∩ NI) = 0.041 x 0.975
P(PT∩ NI) = 0.039975
P(PT) = P(PT∩ I)+P(PT∩ NI)
P(PT)= 0.0226 + 0.039975
P(PT) = 0.062575
P(I/PT) = P(PT∩I)/P(PT)

write an expression that can be used to find the nth term for each sequence listed below.7, 13, 19, 25, 31,.... -1,2,5,8,11,14
LenKa [72]
You'll have to use an arithmetic sequence to find the nth term. Use the equation a=6n+1
Answer:
d = 6+sqrt(42)=12.4807407
Step-by-step explanation:
h= -d² + 12d + 6
The ball is caught at ground level which means h=0
0 = -d² + 12d + 6
Subtract 6 from each side
-6 = -d^2 +12d
Factor out a - sign
-6 =-(d^2-12d)
Divide by -1
6 = d^2 -12 d
Complete the square
-12/2 = -6 then square it = 36
Add 36 to each side
6+36 = d^2 -12d +36
42 = (d-6)^2
Take the square root of each side
±sqrt(42) = sqrt( (d-6)^2)
±sqrt(42) = (d-6)
Add 6 to each side
6±sqrt(42) = (d-6)+6
6±sqrt(42) = d
d = 6+sqrt(42)=12.4807407
d =6- sqrt(42)=-.480740698
Since the distance cannot be negative