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motikmotik
3 years ago
9

tony misplaced 7 stamps from his collection. He knows that each stamp of his worth $0.15 and that the total value of them is now

only $5.55. write an equation to determine the number of stamps (s) that tony originally had.
Mathematics
1 answer:
irinina [24]3 years ago
8 0
First we divide the total value of the stamps he has left with the cost
so its: $5.55÷$0.15 = 37
so now he has 37 stamps
just add the number of his misplaced stamps
37 + 7 = 44
Tony originally had 44 stamps
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The top tree broke and fell over.the remaining tree teunk is 3 feet tall.the tip of the tree rests on the ground 14 feet from th
Bas_tet [7]

Answer:

14.3 feet.

14.3 feet

Step-by-step explanation:

The problem forms a right triangle in which:

The Vertical Leg of the Right Triangle = 3 feet

The Horizontal Leg of the Right Triangle =14 feet

We are to determine the length of the broken part of the tree. This is the Hypotenuse of the Right Triangle,

Using Pythagoras Theorem

Hypotenuse^2=Opposite^2+Adjacent^2\\Hypotenuse^2=14^2+3^2\\Hypotenuse^2=205\\Hypotenuse=\sqrt{205}\\Hypotenuse=14.32\\ \approx 14.3 feet $(to the nearest tenth of a foot).\\Therefore, the lenght of the broken part of the tree to the nearest tenth of a foot is 14.3 feet.

5 0
3 years ago
Which expressions are equivalent to 3 x + 3 * x + y
jasenka [17]

im sorry but i know x=6 if that helps

3 0
3 years ago
PLEASE HELP, I don’t know how to do this...like at all
Svet_ta [14]

Answer:

arc ? = 255°

Step-by-step explanation:

arc DB = 180° - 75° = 105°

arc ? = 360° - 105° = 255°

6 0
2 years ago
10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

5 0
1 year ago
of all the students in class, 1/5 of them walk to school. What percent of students in the class walk to school
bagirrra123 [75]

Answer:

20%

Step-by-step explanation:

1/5 is the same as 2/10

2/10 is the same as 0.2

0.20 is the same as 20%


=) u got it!

7 0
3 years ago
Read 2 more answers
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