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3 years ago

5

A line has a slope of 7 and contains the point (5, −9).

1 answer:

sergejj [24]3 years ago

7 0

Your answer would come out to be y=7x-44
Which would be A, B, and D.
Those match up to that answer.

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Jaya is the middle of three siblings whose ages are consecutive even integers. If the sum of their ages is 84,find Jaya’s age

Svetach [21]

12345612345612317890

7 0

1 year ago

Factor completely. 12x4+18x3+45x2 Enter your answer in the box.

lukranit [14]

QUESTION 1

The given expression is

$12x^4+18x^3+45x^2$

The greatest common factor is $3x^2$ .

We factor to obtain;

$3x^2(4x^2+6x+15)$

QUESTION 2

The given quadratic equation is

$x^2+6x-72=0$

We split the middle term to obtain

$x^2+12x-6x-72=0$

Factor by grouping;

$x(x+12)-6(x+12)=0$

$(x+12)(x-6)=0$

Use zero product property;

$(x+12)=0\:\:or\:\:(x-6)=0$

$x=-12\:\:or\:\:x=6$

QUESTION 3

The given system of equation is

$3x+4y=-8$

$7x-3y=6$

If we multiply $3x+4y=-8$ by 3, we obtain;

$9x+12y=-24$

If we multiply $7x-3y=6$ by 4 we obtain;

$28x-12y=24$

Adding the last two equations will give us;

$37x=0$

The y-variable is eliminated.

Answer:Multiply 3x+4y=−8

by 3. Multiply 7x−3y=6 by 4. Add the resulting equations together.

6 0

3 years ago

Which term describes that right of a lender to sell collateral to get back the principal if the borrower cannot repay the loan?

Pie

Answer:

Lien

Step-by-step explanation:

The correct answer to this question is "Lien". This is the term that describes the right of a lender to sell collateral to get back the principal if the borrower cannot repay the loan is called the lien. Hope this helps answer your question.

3 0

3 years ago

Read 2 more answers

If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec?

dem82 [27]

Answer:

Value of $\sec \theta = \frac{5}{4}$

Step-by-step explanation:

Given: A vertical line is dropped from the x-axis to the point (12, -9) as shown in the diagram below;

To find the value of $\sec \theta$ .

By definition of secants;

$\sec \theta = \frac{1}{\cos \theta}$

Now, first find the cosine of angle $\theta$

As the point (12 , -9) lies in the IV quadrant , where $\cos \theta > 0$

Consider a right angle triangle;

here, Adjacent side = 12 units and Opposite side = -9 units

Using Pythagoras theorem;

$(Hypotenuse side)^2= (12)^2 + (-9)^2 = 144 + 81 = 225$

or

$Hypotenuse = \sqrt{225} =15 units$

Cosine ratio is defined as in a right angle triangle, the ratio of adjacent side to hypotenuse side.

$\cos \theta = \frac{Adjacent side}{Hypotenuse side}$

then;

$\cos \theta = \frac{12}{15} = \frac{4}{5}$

and

$\sec \theta = \frac{1}{\cos \theta}= \frac{1}{\frac{4}{5}} = \frac{5}{4}$

therefore, the value of $\sec \theta$ is, $\frac{5}{4}$

5 0

3 years ago

Read 2 more answers

Given the prime factorisation of the each of

Zigmanuir [339]

The cube root of 287496 is 66

8 0

3 years ago